Answer:
Mass = 14.876 g
Explanation:
Given data:
Volume of gold = 0.77 cm³
Mass of gold = ?
Solution:
Density of gold from literature is 19.32 g/cm³
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
19.32 g/cm³ = m/ 0.77 cm³
m = 19.32 g/cm³ × 0.77 cm³
m = 14.876 g
Explanation:
c Silver is an excellent conductor
hope it helps!
Answer:
20.(45)L or about 20.4545L
Explanation:
PV = nRT
Where:
P - pressure
V - volume
n - number of particle moles
R - a constant
T - temperature in K
We can assume the P and n (and definitely R) stay the same, so we infer that
Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The question is to determine the simplest mass ratio of gold to Chlorine in the compound.
Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:
15.39 / 2.77 = 5.56 g of gold to two decimal places
<em>Therefore, for every 5.56 g of gold, there is 1 g of chlorine.</em>
<em>Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.</em>
