The relationship between mass and inertia is described by newton's second law of motion. true or false

1 answer:

4 0

False. Inertia and mass is not described in Newton’s second law of motion but in Newton’s first law of motion. Newton’s first law of motion or sometimes referred to as the law of inertia. In Newton’s first law indicates that an object at rest will remain at rest unless acted by an unbalanced force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

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A race-car drives around a circular track of radius RRR. The race-car speeds around its first lap at linear speed v_iv i v, st

OLEGan [10]

Answer:

The magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.

Explanation:

The initial centripetal acceleration, a of the race-car around the circular track of radius , R with a linear speed v is a = v²/R.

When the linear speed of the race-car increases to v' = 4v, the centripetal acceleration a' becomes a' = v'²/R = (4v)²/R = 16v²/R.

So the centripetal acceleration, a' = 16v²/R.

To know how much the magnitude of the car's centripetal acceleration changes, we take the ratio a'/a = 16v²/R ÷ v²/R = 16

a'/a = 16

a' = 16a.

So the magnitude of the centripetal acceleration increases by 16 times when the linear speed increases by 4 times.

8 0

3 years ago

A truck is traveling due north at 50 km/hr approaching a crossroad. On a perpendicular road a police car is traveling west towar

kirill [66]

Answer: $45\hat{i}+50\hat{j}$

Explanation:

Truck velocity=50 km/hr

police car velocity =45 km/hr

Let they start at t=0 s

After one hour

truck displacement $=50\times 1=50 km$

In vector Form $(r_1)=50\hat{j}$

For Police car displacement $=45\times 1=45 km$

in vector form $(r_2)=-45\hat{i}$

$r_{12}=50\hat{j}-(-45\hat{i})$

$r_{12}=45\hat{i}+50\hat{j}$

8 0

3 years ago

At an instant when the displacement is equal to a/2, what fraction of the total energy of the system is potential?

madreJ [45]

<span>At an instant when the displacement is equal to a/2, Potential energy U = 1/2ka(square) where a is displacement. when a= a/2 U = 1/4ka(square) U = E/4 Potential Energy = 1/4 Total energy</span>

4 0

3 years ago

A cube with 30-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t

OleMash [197]

Answer:

A) hydrostatic force on top of cube = 882.9N

B) hydrostatic force on sides of cube = 0N

Explanation:

Detailed explanation and calculation is shown in the image below