Answer:
The magnitude of the resistive force exerted by the water is
newtons.
Explanation:
By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:
(Eq. 1)
Where:
- Forward trust, measured in newtons.
- Resistive force exerted by the water, measured in newtons.
From (Eq. 1), we get that: (
)
![R = F](https://tex.z-dn.net/?f=R%20%3D%20F)
![R = 6.85\times 10^{5}\,N](https://tex.z-dn.net/?f=R%20%3D%206.85%5Ctimes%2010%5E%7B5%7D%5C%2CN)
The magnitude of the resistive force exerted by the water is
newtons.
<span>the answer is energy is not created nor destroyed, but it can change from one energy form to another.</span>
Ground water keept the ground at a stable level when it is gone the cavern it was in has no support and is at risk of callaps
First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force,
![\mu m g](https://tex.z-dn.net/?f=%5Cmu%20m%20g)
. For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
![ma=-\mu m g](https://tex.z-dn.net/?f=ma%3D-%5Cmu%20m%20g)
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
![a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2](https://tex.z-dn.net/?f=a%3D-%280.220%29%289.81%20m%2Fs%5E2%29%3D-2.16%20m%2Fs%5E2)
Now we can use the following relationship to find the distance covered by the skier before stopping, S:
![2aS=v_f^2-v_i^2](https://tex.z-dn.net/?f=2aS%3Dv_f%5E2-v_i%5E2)
where
![v_f=0](https://tex.z-dn.net/?f=v_f%3D0%20)
is the final speed of the skier and
![v_i=4.75 m/s](https://tex.z-dn.net/?f=v_i%3D4.75%20m%2Fs)
is the initial speed. Substituting numbers, we find: