All categories

3 years ago

For a star with a parallax angle of 1/2 of an at arcsecond, what will be its distance in parsec?

Physics

1 answer:

avanturin [10]3 years ago

8 0

(1 parsec) is the distance at which an object has a parallax of 1 arcsecond. The distance is about 3.26 light years.

Another way to understand it is: The distance from which the Earth's orbit appears 1 arcsecond across.

For a parallax angle of 1/2 arcsecond, the distance is <em>2 parsecs </em>(about 6.52 light years).

1 arcsecond is 1/3600 of a degree, 0.00028 degree.

You might be interested in

How do you do this problem?

mojhsa [17]

Answer:

Explanation:

When A and B come in contact with each other, +12 - 12 = 0 so their changes cancel.

Now C has a charge of +12

When A and C come together they each have an equal share of that 12, so each of them has 6

So the answer is

A B C

6 0 6

which is C

4 0

3 years ago

When an object falls, it trades gravitational potential energy for kinetic energy, accelerating toward the ground. calculate the

liq [111]

The speed of the energy decreases

5 0

3 years ago

The top speed you will ever need to go in a parking lot is_

Kruka [31]

10 mph i jus got it right on the test

3 0

3 years ago

Razona si, en las experiencias de Faraday, el efecto producido moviendo el circuito será el mismo que el producido moviendo el i

const2013 [10]

Answer:

moving the circuit or the magnet gives the same result

Explanation:

The faraday effect establishes that the temporal variation of imaginative flow produces an electric potential

fem = $\frac{d \phi }{dt}$ dfi / dt

the magnetic flux is

Ф = B. A = B A cos θ

suppose for simplicity that the angle is zero so cos 0 = 1

Φ = B A

By analyzing this expression, the change in magnetic flux can converge while keeping the magnetic field fixed and varying the electric field or keeping the electric field fixed and varying the magnetic field.

Consequently moving the circuit or the magnet gives the same result

5 0

2 years ago

A wire is stretched between two posts. Another wire is stretched between two posts that are four times as far apart. The tension

Elena-2011 [213]

Answer:

Therefore,

The speed of the wave on the longer wire is 95 m/s.

Explanation:

Given:

For Short wire, speed is

$v_{s}=190\ m/s$

Let length of Short and Longer wire be $L_{s}\ and\ L_{l}$ such that

$L_{l}=4\times L_{s}$

To Find:

$v_{l}=?$ Speed on the longer wire

Solution:

The speed of a pulse or wave on a string under tension can be found with the equation,

$v=\sqrt{\dfrac{F_{T}\times L}{m}$

Where,

$F_{T}$ = Tension on the wire

L = Length of Sting

m = mass of String

So here we have,

$F_{T}$ = same

$L_{l}=4\times L_{s}$

Therefore,

$v_{s}=\sqrt{\dfrac{F_{T}\times L_{s}}{m}$ ......equation ( 1 )

And

$v_{l}=\sqrt{\dfrac{F_{T}\times L_{l}}{m}$ .......equation ( 2 )

Dividing equation 1 by equation 2 and on Solving we get

$\dfrac{v_{s}}{v_{l}}=\sqrt{\dfrac{L_{s}}{L_{l}}}$

Therefore,

$v_{l}=v_{s}\sqrt{\dfrac{4\times L_{s}}{L_{s}}}=190\times 2=380\ m/s$

Therefore,

The speed of the wave on the longer wire is 95 m/s.

8 0

3 years ago