Let’s come back to the equation of SPEED OF AN ECHO
SPEED =2XDISTANCE/ TIME
So 337*7/2=1179.5 nearest meter =1800 m away
Hope you will get it right
The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.
The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.
Distance traveled = Velocity × Time
Given in the question
Velocity of the plane = 1200 Km/h
Time Traveled = 2.5 h
Put in the value, we get
Distance traveled = 1200 × 2.5
Distance traveled = 3000 Km
Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.
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A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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The distances to the most of these galaxies estimated from their red shifts and the application of Hubble's Law.
<h3>What is Hubble's Law?</h3>
The discovery in physical cosmology that galaxies are travelling away from Earth at rates proportionate to their distance is known as Hubble's law, often referred to as the Hubble-Lemaître law or Lemaître's law. In other words, they are travelling away from Earth more quickly the more away they are. The redshift of the galaxies—a shift in the light they produce toward the red end of the visible spectrum—has been used to calculate their velocities.
The Sloan Digital Sky Survey includes many thousands of galaxies in its spectroscopic catalogs. The distances to the most of these galaxies estimated
from their red shifts and the application of Hubble's Lawh
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A projectile has a vertical acceleration of -9.8 m/s² in all its points, and at the highest point in the trajectory his velocity is zero in the vertical direction.
The correct option is C.
