1. In this activity, you will be looking for a relationship between the mass of the cart and the acceleration of the cart.

George walks to a friend's house. He walks 750 meters North, then realizes he walked

Sauron [17]

Answer:

I think you are looking for the velocity, so the answer is 38.5 m/s

Explanation:

Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.

4 0

3 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

Sedaia [141]

Answer:

$a_2\ =\ -33.65\ m/s^2$

Explanation:

Given,

For the first rocket,

Initial velocity of the first rocket A = $u_1\ =\ 4600\ m/s.$

Acceleration of the first rocket = $a_1\ =\ -18\ m/s^2$

For the second rocket,

Initial velocity of the second rocket B = $u_2\ =\ 8200 m/s.$
Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

$\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec$

Let $a_2$ be the acceleration of the second rocket B for the same time interval

from the kinematics,

$\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\$

$\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2$

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0

3 years ago

Water flows over a section of Niagara Falls at a rate of 2.2 × 106 kg/s and falls 65 m. What is the power wasted by the waterfal

Irina-Kira [14]

Answer:

P = 1401.4 x 10⁶ W

Explanation:

Given that

Water flow rate m = 2.2 x 10⁶ kg/s

Height ,h= 65 m

Acceleration due to gravity ,g= 9.8 m/s²

The power P is given as

P= m g h

P=Power

m=Water flow rate

h=height

Now by putting the values in the above equation

P = 2.2 x 10⁶ x 9.8 x 65 W

P = 1401.4 x 10⁶ W

Therefore the power wasted will be 1401.4 x 10⁶ W.

7 0

3 years ago

How high up is a 3 kg object that has 300 joules of energy

kvasek [131]

Answer:

Height, h = 10.20 meters

Explanation:

It is given that,

Mass of the object, m = 3 kg

Energy of object, E = 300 J

Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :

$E=mgh$

$h=\dfrac{E}{mg}$

$h=\dfrac{300\ J}{3\ kg\times 9.8\ m/s^2}$

h = 10.20 meters

So, the object will move to height of 10.20 meters. Hence, this is the required solution.

5 0

4 years ago

Read 2 more answers

Rearranging the equation m= 5Kg and a= 2 m\s2

olganol [36]

The force of the object with the given mass and acceleration is determined as 10 N.

<h3>Force of the object</h3>

The force of the given object is calculated from Newton's second law of motion as follows;

F = ma

where;

m is mass of the object = 5 kg
a is acceleration of the object = 2 m/s²

F = 5 x 2 = 10 N

Thus, the force of the object with the given mass and acceleration is determined as 10 N.

The complete question is below:

Rearranging the equation m = F/a and solve for F, m= 5Kg and a= 2 m\s2

Learn more about force here: brainly.com/question/12970081

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6 0

2 years ago