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Ganezh [65]
3 years ago
8

1. In this activity, you will be looking for a relationship between the mass of the cart and the acceleration of the cart.

Physics
1 answer:
posledela3 years ago
7 0

Answer:

Mass of cart

Explanation:

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1. An object moving with velocity 15 ms accelerates at 2 m/s for 5 seconds. Calculate the final velocity.​
DedPeter [7]

Answer:

final velocity=u+at 15+2×5=25

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2 years ago
A battery uses _________________ energy to generate _______________ energy.
Alisiya [41]

Uses chemical and generates electrical
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4 years ago
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A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
3 years ago
What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile
vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, P=100\times 10^6\ N/m^2=10^8\ Pa

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

4 0
4 years ago
Children make toy telephones by sticking each end of a long string through a hole in the bottom of a paper cup and knotting it s
Darina [25.2K]

Answer:

The bottom of the cup passes the sound waves to the string, and so on to the other cup. You can hear surprisingly far using a string telephone if help the right way! If the string is kept tight, the sound waves will travel.

Explanation:

3 0
3 years ago
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