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Answer:
There is an attractive force between the rod and sphere.
Explanation:
When negatively charged rod is placed close to the metal sphere then due to the electric field of the rod the opposite free charge of metal sphere comes closer to the rod on one surface
While similar charge in the metal sphere move away from the rod due to repulsion of electric field of rod
This temporary charge distribution of the metal sphere is known as induction
And since opposite charge on the metal surface comes closer to the metal sphere so here we can say that the rod will attract the metal sphere
so here correct answer will be
There is an attractive force between the rod and sphere.
Answer:
<em>The force that would be applied on the rope just to start moving the wagon is 122 N</em>
Explanation:
Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move can be calculated using equation 1.
F = μ x mg .............................. 1
where F is the frictional force;
μ is the coefficient of friction ( μs, in this case, static friction);
m is mass of the object and;
g is the acceleration due to gravity( a constant equal to 9.81 m/
)
from the equation we are provide with;
μs = 0.25
m = 50 kg
g = 9.81 m/
F =?
Using equation 1
F = 0.25 x 50 kg x 9.81 m/
F = 122.63 N
<em>Therefore a force of 122 N must be applied to the rope just to start the wagon.</em>
Answer:
Aphelion: 6404 W/m2
Perihelion: 14978 W/m2
Explanation:
The solar energy flux depends on the solar power output divided by the surface of a sphere with a radius equal to the distance to the Sun.

The distances we need are the aphelion and perihelion of Mercury.
Planetary orbits are ellipses. In an ellipse the eccentricity is related to linear eccentricity and the length of the semi major axis:

Where
e: eccentricity
c: linear eccentricity
a: semi major axis
The linear eccentricity is equal to the distance of the focus of the center of the ellipse.

a = 0.39 AU = 5.83e10 m

In planetary orbits the Sun is in one of the fucuses. With this we can calculate the prihelion and aphelion as:
Ap = a + c = 5.83e10 + 1.22e10 = 7.05e10 m
Pe = a - c = 5.83e10 - 1.22e10 = 4.61e10 m
And the solar energy fluxes will be:


Answer:
speed =distance/time taken
5 m/s