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nadezda [96]
3 years ago
11

An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish? (Work: W = Fd)

Physics
2 answers:
alisha [4.7K]3 years ago
6 0

Answer: 4500 J

Explanation:

The work done by the eagle is given by the product between the force applied and the distance covered:

W=Fd

where

F=90 N is the force applied

d=50 m is the distance covered

Substituting these data into the formula, we find the work done

W=Fd=(90 N)(50 m)=4,500 J

Leno4ka [110]3 years ago
4 0
<span>Work: W = Fd. 50(distance) multiplied by 90(force) would equal 4500 J or, answer D</span>
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Answer:

More force

Explanation:

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According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

  Net force  = mass x acceleration

Now, if a body has more mass and needs to accelerate at the same rate as another one with a lower mass, the force on it must be increased.

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2 years ago
A 20 μF capacitor initially charged to 30 μC is discharged through a 1.5 kΩ resistor. Part A How long does it take to reduce the
Natasha_Volkova [10]

Answer:

it will take 36.12 ms to reduce the capacitor's charge to 10 μC

Explanation:

Qi= C×V

then:

Vi = Q/C = 30μ/20μ = 1.5 volts

and:

Vf = Q/C = 10μ/20μ = 0.5 volts

then:

v = v₀e^(–t/τ)  

v₀ is the initial voltage on the cap  

v is the voltage after time t  

R is resistance in ohms,  

C is capacitance in farads  

t is time in seconds  

RC = τ = time constant  

τ = 20µ x 1.5k = 30 ms  

v = v₀e^(t/τ)  

0.5 = 1.5e^(t/30ms)  

e^(t/30ms) = 10/3  

t/30ms = 1.20397

t = (30ms)(1.20397) = 36.12 ms

Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.

7 0
3 years ago
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S_A_V [24]

Answer:

The distance represents the difference of the first position and last position of the body.

Explanation:

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4 0
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Balanced force

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7 0
3 years ago
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Answer:

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