Ask question

Ask question

All categories

3 years ago

10

Suppose that the mirror described in Part A is initially at rest a distance R away from the sun. What is the critical value of a

rea density for the mirror at which the radiation pressure exactly cancels out the gravitational attraction from the sun?

1 answer:

Sati [7]3 years ago

5 0

Ans;

6.25m²/Kd

Explanation: see attached file

You might be interested in

A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of

Rudiy27

Answer:

Explanation:

Given

mass of spring $m=100\ gm$

extension in spring $x=5\ cm$

downward velocity $v=70\ cm/s$

Position in undamped free vibration is given by

$u(t)=A\cos \omega _0t+B\sin \omega _0t$

where $\omega _0^2=\frac{k}{m}$

also $\frac{k}{m}=\frac{g}{L}$

$\omega _0^2=\frac{k}{m}=\frac{9.8}{0.05}$

$\omega _0=14$

$u(t)=A\cos(14t)+B\sin(14t)$

it is given

$u(0)=0$

$u'(0)=70\ cm/s$

substituting values we get

$A=0$

$u(t)=B\sin (14t)$

$u'(t)=14B\cos (14t)$

$70=14B$

$B=\frac{10}{2}$

$B=5$

$u(t)=5\sin (14t)$

3 0

3 years ago

A compass taken to Earth's moon does not point in a specific direction on the moon.

yKpoI14uk [10]

C) the moon does not have a strong magnetic field

5 0

3 years ago

Read 2 more answers

Given that the speed of sound in air is 330m/s ,calculate the frequency of a note which setup a wavelength of 5cm in air.Is this

Pie

Explanation:

v = wavelength x frequency

330 = 5 . 10-² m x f

f = 6600 Hz

the frequency that human can hear is about 20 Hz - 20000 Hz

so human can hear the note.

3 0

4 years ago

Read 2 more answers

The electric force between two charged objects is influenced by

tresset_1 [31]

<span> attraction between the relative abundance of electrons in one object and protons in the other

</span>

7 0

4 years ago

What is the force when ur pulling heavy furniture that wont budge

elena55 [62]

Answer:

Gravity? is it multiple choice?

3 0

3 years ago

Read 2 more answers