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3 years ago

10

Suppose that the mirror described in Part A is initially at rest a distance R away from the sun. What is the critical value of a

rea density for the mirror at which the radiation pressure exactly cancels out the gravitational attraction from the sun?

1 answer:

Sati [7]3 years ago

5 0

Ans;

6.25m²/Kd

Explanation: see attached file

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You are on an airplane traveling with a constant velocity at an altitude of 20,000m. What is the acceleration of gravity at that

-BARSIC- [3]

The correct answer would be A.The acceleration of gravity is <span>9.81 m/s^2. This is calculated by using the equation:

a = GM/r</span>²

where G is the gravitational constant 6.6726 x 10-11N-m2/kg2, M is the mass of the planet (<span>5.9736E+24 kg) and r is the radius of the planet.
</span>

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3 years ago

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A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

nexus9112 [7]

Answer:

$y=2.64m$

Explanation:

Given data

Ball one

mass m₁=3.0kg

velocity v₁=20 m/s

Ball second

mass m₂=2.0 kg

velocity v₂=12 m/s

First we need the speed of combined ball.Since the system conserves the linear momentum

$p_{i}=p_{f}\\m_{1}v_{1}+m_{2}v_{2}=m_{t}v_{t}$

So the combined velocity vt is:

$v_{t}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{t}}\\$

Since the two balls 1 and 2 are moving in opposite direction

So

$v_{t}=\frac{m_{1}v_{1}-m_{2}v_{2}}{m_{t}}\\$

Substitute the given values

$v_{t}=\frac{(3kg)(20m/s)-(2kg)(12m/s)}{(3+2)kg}\\ v_{t}=7.2 m/s$

We have the equation for motion with constant acceleration is given by:

$v^2=v_{o}^2+2g(y-y_{o})\\$

At initial position y₀=0 and vt=v-v₀

So

$v^{2}=v_{o}^2+2g(y-0)\\ y=\frac{v^2-v_{o}^2}{2g}\\ y=\frac{v_{t}^2}{2g}\\ y=\frac{(7.2m/s)^2}{2(9.8m/s^2)}\\ y=2.64m$

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3 years ago

Which one of the following statements contain a simile?

Alex73 [517]

Do u have the statements ?

5 0

2 years ago

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If earth had no atmosphere, would a falling object ever reach terminal velocity?

stepan [7]

No, because terminal velocity is when the acceleration of the Earth’s gravity is balanced by the air resistance of the atmosphere.

5 0

3 years ago

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

PtichkaEL [24]

Answer:

533.33 nm

Explanation:

Since dsinθ = mλ for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.

Since the fringes coincide,

m'λ = m"λ'

λ' = m'λ/m"

= 10 × 640 nm/12

= 6400 nm/12

= 533.33 nm

8 0

2 years ago