and closing
.
The heart has 4 valves. They are what makes the lub-dub lub-dub sounds that can be heard from the chest.
The mitral valve is located between the left atrium and the left ventricle. It closes the left atrium to collect oxygenated blood from the lungs and opens to pass it on to the left ventricle.
The tricuspid valve is located between the right atrium and the right ventricle. It closes the right atrium to hold unoxygenated blood and opens to pass it on to the right ventricle ensuring a one way flow.
The aortic valve is located between the aorta and the left ventricle. It closes the left ventricle and opens to the aorta to pass on the oxygen-rich blood to the body.
The pulmonary valve is located between the pulmonary artery and the right ventricle. It closes off the right ventricle and opens to pass on unoxygenated blood to the lungs.
Answer:
I think the answer is electric potential.
Answer
given,
mass of the stick = 290 grams = 0.29 Kg
Force on the stick on one side = F = 9 N
force acting perpendicular to stick.
magnitude of acceleration
rate of change of angular momentum is equal to Force
rate of change of angular momentum = 9 N
F = m a
a = 31.034 m/s²
Direction of motion will in the direction of force application or in the direction of change of velocity
Answer:
b
c
e
h
Explanation:
Note that the swing direction was not giving in the question and direction could be sideways (in a turn) or in a track or both
The question show something in common ...acceleration
So let's look at the statements and pick the correct ones
a is false while b is correct as the train is accelerating
c is correct. The train is accelerating even thou the speed could not be ascertained
d is false and not feasible as the train is accelerating
e is true as the train maybe moving at a constant speed in a circle
f is false. This could be constant velocity in a circle. Same as g (false)
h is true. It's accelerating
Answer:
f = 6.66 cm
Explanation:
For this exercise we will use the constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length, p is the distance to the object and q is the distance to the image
the expression for magnification is
m = h '/ h = - q / p
with this we have a system of two equations with two unknowns, in the problem they give us the distance to the image q = 10 cm and a magnification of m = -0.5
-0.5 = - q / p
p = - q / 0.5
p = - 10 / 0.5
p = 20 cm
now we can with the other equation look for the focal length
1 / f = 1/20 + 1/10
1 / f = 0.15
f = 6.66 cm