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3 years ago

Why don't the praticles in a solid move past one another

2 answers:

6 0

Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. Their vibration is related to their kinetic energy. In the solid the particles vibrate in place.

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Ne4ueva [31]3 years ago

3 0

Answer:

Particles in a solid object are super tight and close to eachother. They do not move past eachother because it is a solid, not a liquid or gas.

Explanation:

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What is the mass of 0.28 mole of iron?

vredina [299]

Answer:

Your answer should be 15.68 grams.

Explanation:

Seeing as 1 mole has a mass of 56 g, 56*0.28 would get you 15.68 g.

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3 years ago

Read the reaction and the statement. H2(g) + I2(g) ⇌ 2HI(g) The concentration of H2, I2 and HI are measured as 0.04 M, 0.08 M an

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3 years ago

A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a

Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

$H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)$

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = $m C .$ Δ $T$

m is mass of the solution = 151.8 mL * $\frac{1 g}{1 mL} = 151.8 g$

C is the specific heat of solution = 4.18 $\frac{J}{g. ^{0}C}$

ΔT is the temperature change = $31.50^{0}C - 21.45^{0}C = 10.05^{0}C$

q = $151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J$

Moles of NaOH = $101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol$ NaOH

Moles of $H_{2}SO_{4}$ = $50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}$

Enthalpy of the reaction = $\frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol$

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3 years ago

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

777dan777 [17]

The molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = $\frac{A}{cl}$

ξ = $\frac{1.140}{1.5*10^{-4}*0.5 }$

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = $\frac{1.140}{0.000075}$

Performing division to find the value of molar extinction coefficient

ξ = 15,200 $M^{-1} cm^{-1}$

Hence, the molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

Learn more about molar extinction coefficient -

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1 year ago

Why is propionic acid soluble in water

omeli [17]

HSDB and the SRC Physical Properties database database reports that propionic acid has a water solubility of 1000 g/l at 25 °C. Ullmann and Knovel Solvents - A Properties Database reports that propionic acid is miscible in any ratio with water.

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3 years ago