Answer:
its molecular formula must be C10H16O with 2 rings.
Explanation:
the number of rings of the camphor has to be calculated, we have M + = 152.12 in the mass spectrum and it has three double bonds and one ring. The base beak has great abundance.
Since camphor is a single ketone, and M+/MC = 12 ~~ 8, its molecular formula must be C10H16O, accordingly, the number of rings = (10 * 2-16)/2 = 2.
Get to know first how many moles in the gas:n = pV/RT= (1.013*10^5*750/760) Pa *1.49*10^-3 m^3/(8.314 J/(molK)*298) n = 0.0601 moles.
The combustion energies are 889 kJ/mol (methane) and 2 220 kJ (propane) x = moles methane, y = moles propane
x*889 + y*2220 = 778 x + y = 0.0601----------- x = 0.267784 moles = 0.267784*100/0.0601 = 44.6 % y = 0.243216 moles = 0.243216*100/0.0601 = 55.4 %
Answer:
There are 0.1 moles of solute in 250 mL of 0.4 M solution
Explanation:
because it is
Answer:
There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout. The most common type of homogenous mixture is a solution, which can be a solid, liquid, or gas.
Hope this helped :)
The best answer is Titanium
