1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
m_a_m_a [10]
3 years ago
8

The different combinations that genes within a population can have is known as

Chemistry
1 answer:
podryga [215]3 years ago
7 0

Answer:

genetic variation

Explanation:

it just is

You might be interested in
HELP ME!! THANH YOU If an atom has 80 protons and 121 neutrons, and is not in an excited state, how many electrons would Bohr sa
wariber [46]
I think it might be 80
5 0
3 years ago
A 33.69 g sample of a substance is initially at 29.4 °c. after absorbing 1623 j of heat, the temperature of the substance is 110
Sliva [168]
Q= mcΔT
1623 = 33.69g x c x (110.8 - 29.4)
1623 = 2742.366 g•°C x c
c = 0.59j/g•°C
4 0
3 years ago
TRUE or FALSE: The rock closest to the ridge is newer and younger than the older rock
alina1380 [7]

Answer:true

Explanation:

7 0
3 years ago
What is the electron configuration for La (lanthanum)?
MrRissso [65]

Answer:

Lathanum .

Atomic number = 57

Symbol = La

Atomic weight = 138.9

No of energy orbitals = 6

Electronic configuration

[Xe]6s^25d^1

7 0
3 years ago
A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál
Svetllana [295]

Answer:

\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

m_T=180g+120g+135g+2.77g=437.77g

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%

¡Saludos!

5 0
3 years ago
Other questions:
  • A certain block is floating in water with 77% of itself submerged. It has a length of 4.3 cm, a width of 5.9 cm, and a height of
    11·1 answer
  • An air temperature of 95°C most often exists in which layer of the atmosphere?
    9·1 answer
  • What color does copper produce when it reacts to chlorine
    9·1 answer
  • How would Mg change to gain a noble gas structure?<br><br> lose 2 electrons<br> gain 6 electrons
    10·2 answers
  • Ozone layer depletion causes
    9·1 answer
  • Addition of 6 M HCl to which substance will not result in gas evolution? Please explain why.A) AlB) ZnC) K2CO3D) NaNO3
    8·1 answer
  • Chemical Equations and Reactions WS
    10·1 answer
  • How many atoms are in 25.0 moles of calcium (Ca)?
    10·1 answer
  • Please help!!! will give 25 points!
    13·1 answer
  • Which statement best describes the role of oxygen in cellular respiration?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!