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yarga [219]
3 years ago
8

How to solve 3/2(6) -3 + 5/3 (3)

Mathematics
1 answer:
Gennadij [26K]3 years ago
5 0

Answer:

11

Step-by-step explanation:

3/2(6) - 3 + 5/3(3)

1) Multiply fractions with the numbers in parentheses next to them.

18/2 - 3 + 15/3

2) Simplify fractions.

9 - 3 + 5

3) Subtract

6 + 5

4) Add

11

Final answer: 11

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The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = –x + 6. What is the point-slope form
murzikaleks [220]
Y = mx + b is <span> the "slope-intercept" form of the equation of a line ;
We have y = -x + 6 ;
Then, m = - 1 ;

</span><span>The "point-slope" form of the equation of a straight line is:
</span><span>y - y1 = m(x - x1) ; 
But, x1 = - 3 and y1 = 8 ;
We have y - 8 = (-1)( x + 3 );
Finally, y - 8 = -( x + 3 );
 The right answer is the fourth choice;
________________________________________

</span><span>y – 3 = (x – 1) ; the equation becames
</span>
y = x + 2 ; 
The right answer is the third choice;

6 0
2 years ago
Read 2 more answers
Can someone explain how they get the answer.
SSSSS [86.1K]

Answer:

585°

Step-by-step explanation:

2 π  = 360° = 180/pi

(13pi/4) x (180/pi)

(13/4) x (180/1)

(13/1) x (45/1)

585°

3 0
3 years ago
Read 2 more answers
I am stuck. Please help.
natulia [17]

Answer:

the first one: 24.8

the second one: 2012

5 0
2 years ago
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The difference of three times a number and 4 is -15
attashe74 [19]

Answer:

Let the number be n.

3n - 4= -15

3n= -15+4

3n= -11

n= -11/3

n= -3.67 or n= -3 2/3

Step-by-step explanation:

Bring over 4 to the RHS of the equation and divide the RHS by 3.

4 0
3 years ago
Find the average value of f over region
SVETLANKA909090 [29]
D is a right triangle with base length 1 and height 8, so the area of D is \dfrac12(1)(8)=4.

The average value of f(x,y) over D is given by the ratio

\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}

The denominator is just the area of D, which we already know. The average value is then simplified to

\displaystyle\frac74\iint_Dxy\,\mathrm dA

In the x,y-plane, we can describe the region D as all points (x,y) that lie between the lines y=0 and y=8x (the lines which coincide with the triangle's base and hypotenuse, respectively), taking 0\le x\le1. So, the integral is given by, and evaluates to,

\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx
=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx
=14x^4\bigg|_{x=0}^{x=1}
=14
3 0
3 years ago
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