What type of fault involves compression?

Suppose the Sun were suddenly to shrink in size but that its mass remained the same. According to the law of conservation of ang

labwork [276]

I think its angular velocity would increase

8 0

4 years ago

A 2.16 x 10-2-kg block is resting on a horizontal frictionless surface and is attached to a horizontal spring whose spring const

pochemuha

Answer:

0.15694 m

Explanation:

m = Mass of block = $2.16\times 10^{-2}\ kg$

v = Velocity of block = 11.2 m/s

k = Spring constant = 110 N/m

Here the kinetic energy of the fall and spring are conserved

$\frac{1}{2}mv^2=\frac{1}{2}kA^2\\\Rightarrow mv^2=kA^2\\\Rightarrow A=\sqrt{\frac{mv^2}{k}}\\\Rightarrow A=\sqrt{\frac{2.16\times 10^{-2}\times 11.2^2}{110}}\\\Rightarrow A=0.15694\ m$

The amplitude of the resulting simple harmonic motion is 0.15694 m

3 0

4 years ago

An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached

Hatshy [7]

Answer:

(a) Both the charges are positive or negative.

(b) Teh value of each charge is 1.53 x 10^-5 C.

Explanation:

Spring constant, K = 340 N/m

Natural length, L = 0.4 m

stretch, y = 0.033 m

(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.

(b) The electrostatic force is balanced by the spring force.

$\frac{kq^2}{(L + y)^2}=Ky\\\\\\\frac{9\times 10^9 q^2}{(0.4 +0.033)^2} = 340\times0.033\\\\q= 1.53\times 10^{-5} C$

6 0

3 years ago

An 11,000-watt radio station transmits at 880 kHz. Calculate the energy of a single photon at the transmitted frequency.

prisoha [69]

The energy of a single photon at the transmitted frequency is $\bold{5834.4 \times 10^{-31} \mathrm{J}}$

Answer: Option b

<u>Solution:</u>

Energy of photon is given as $E=\frac{h c}{\lambda}$

Where c is the velocity of Light $\left(3 \times 10^{8} m / s\right)$

h is planck's constant $\left(6.63 \times 10^{-34}\right)$

λ is the wavelength of photon

Energy of photon can be rewritten as $E=h \times f$

Where f is the frequency of photon

Frequency of photon is obtained by dividing velocity of light by wavelength of photon.

$f=\frac{c}{\lambda}$

$E=6.63 \times 10^{-34} \times 880 \times 10^{3}=5834.4 \times 10^{-31} \mathrm{J}$

8 0

3 years ago

What is the momentum of a 65kg ball rolling at 5 m/s?

mojhsa [17]

Explanation:

Momentum = mass × velocity

p = (65 kg) (5 m/s)

p = 325 kg m/s

7 0

3 years ago