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3 years ago

What is the mathematical relationship between voltage (V), resistance (R), and current (I)? Express your answer as an equation:

Physics

1 answer:

Lemur [1.5K]3 years ago

3 0

V=IR
I=V/R
R=V/I
these are the realations of voltage ,resistance , and current .

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A nonmechanical water meter could utilize the Hall effect by applying a magnetic field across a metal pipe and measuring the Hal

Serga [27]

Answer:

The velocity is $v =2.455 \ m/s$

Explanation:

From the question we are told that

The diameter of the pipe is $d = 4.25 \ cm = 0.0425 \ m$

The magnetic field is $B = 0.575 \ T$

The hall voltage is $V_H = 60.0 mV = 60 *10^{-3} \ V$

Generally the average fluid velocity is mathematically represented as

$v = \frac{V}{ B * d }$

=> $v = \frac{60*10^{-3}}{ 0.575 * 0.0425 }$

=> $v =2.455 \ m/s$

5 0

3 years ago

A vessel is filled with a liquid of density 1900 kg/m3 . There are two holes (one above the other) in the side of the vessel. Li

FromTheMoon [43]

Answer:

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity = 9.8 m/s²

the speed at each point

$v = \sqrt{2gh}$

for upper hole $v = \sqrt{2\times 9.8 \times 19}$

v = 19.29 m/s

lower hole $v = \sqrt{2\times 9.8 \times 117}$

v = 47.88 m/s

The path for each is parabolic

x = v t

$y = \dfrac{1}{2}gt^2$

$y = \dfrac{1}{2}g(\dfrac{x}{v})^2$

$y = \dfrac{gx^2}{2v^2}$

we get

upper hole

$y = \dfrac{9.8\times x^2}{2\times 19.29^2}= 0.0132 x^2$ lower hole

$y= \dfrac{9.8\times x^2}{2\times 47.88^2}=0.00214x^2$ y for upper hole = 80 + y for lower hole

$0.0132 x^2= 98 + 0.00214 x^2$

$0.0082 x^2 = 98$

x = 109.32 meters

110 meters is the distance where they will intersect

4 0

3 years ago

The orbital period of a satellite is 2 x 106 s and its total radius is 2.5 x 1012 m.

MrMuchimi

Explanation:

Orbital period = 2 x 10⁶s

Total radius = 2.5 x 10¹²m

Unknown:

Tangential speed of the satellite = ?

Solution:

The tangential speed simply expresses the rate at which the distance moves around its orbit with time.

Since the orbit is taken to be circular;

Tangential speed = $\frac{2 x pi x r}{t}$

r is the radius

t is the time or orbital radius

Tangential speed = $\frac{2 x 3.14 x 2.5 x 10¹²}{2 x10[tex]^{6}$ }[/tex]

Tangential speed = 7.85 x 10⁶m/s

Learn more:

Circular motion brainly.com/question/2562955

#learnwithBrainly

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