Answer:
The force of friction is 15.68 N.
Explanation:
Given:
Rise is 6 m and run is 8 m.
Mass of each body (m) = 4 kg
The whole system is in equilibrium.
Now, consider the diagram below representing the scenario given in the question.
The forces acting on the mass that is hanging are tension force in the upward direction and weight of the body acting vertically downward.
As the mass is in equilibrium, the total upward force equals total downward force. So,
-------- (1)
Now, the forces acting on the other mass along the ramp are:
1. Tension (T) up the ramp
2. and frictional force (f) down the ramp
Now, as per question:
Rise = 6 m and run = 8 m
So, from figure,
Now,
Now, as the other mass is also at rest, net force acting on it is also 0. So,
Now, plug in the given values and solve for 'f'. This gives,
Therefore, the force of friction is 15.68 N
