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3 years ago

Explain briefly why metals are good conductors of electric current

2 answers:

7 0

The free electrons in metals can move through the metal, all while receiving and losing electrons, allowing metals to conduct electricity. Example: copper is a great conductor of electric current.

harina [27]3 years ago

7 0

Hello!

Just briefly, Metals are good conductors of electricity because of electrons moving freely in metals and metals like to give up electrons making them a great conductor of electricity.

Hope this helps! Thank you!!

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On earth which of the following are being investigated to contain fusion reactions

Vera_Pavlovna [14]

Answer:

A. Inertial Confinement and B. Magnetic Confinement

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3 years ago

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A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the

Bond [772]

Momentum of the car is 46.2 kgm/s

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3 years ago

Playing near a road construction site, a child falls over a barrier and down onto a dirt slope that is angled downward at 33° to

Debora [2.8K]

Answer:

$\mu_{k} \approx 0.719$

Explanation:

The equations of equilibrium for the child are: (x' in the direction parallel to slope, y' in the direction perpendicular to slope)

$\Sigma F_{x'} = m\cdot g \cdot \sin \theta - \mu_{k}\cdot N = m\cdot a\\\Sigma F_{y'} = N - m\cdot g\cdot \cos \theta = 0$

After some algebraic manipulation, an expression for the coefficient of kinetic friction is obtained:

$m\cdot g\cdot \sin \theta - \mu_{k}\cdot m \cdot g \cos \theta = m \cdot a$

$g \cdot (\sin \theta - \mu_{k}\cdot \cos \theta) = a$

$\mu_{k}\cdot \cos \theta = \sin \theta - \frac{a}{g}$

$\mu_{k} = \frac{1}{\cos \theta}\cdot (\sin \theta - \frac{a}{g} )$

$\mu_{k} = \frac{1}{\cos 33^{\textdegree}}\cdot \left(\sin 33^{\textdegree}-\frac{(-0.57\,\frac{m}{s^{2}}) }{9.807\,\frac{m}{s^{2}} } \right)$

$\mu_{k} \approx 0.719$

5 0

3 years ago

A block of mass m is compressed against a spring (spring constant kk) on a horizontal frictionless surface. The block is then re

Nimfa-mama [501]

Answer:

A) True, B) False, C) False and D) false

Explanation:

Let's solve the problem using the law of conservation of energy to know if the statements are true or false

Let's look for mechanical energy

Initial

Emo = Ke = ½ k Dx2

Final

Em1= ½ m v12

Emo = Em1

½ k Δx2 = ½ m v₁²

v₁² = k / m Δx²

v₁ = √ k/m Δx

Now let's calculate the speed when it falls

Vfy² = Voy² - 2gy

Vfy² = - 2gy

Vf² = v₁² + vfy²

A) True v₁ = A Δx

.B) False. As there is no rubbing the mechanical energy conserves

.C) False the velocity is proportional to the square root of the height

v2y = v2 √2

. D) false promotional compression speed

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3 years ago

50 J of work was done in order to move a chair 5 meters. what was the force applied to the chair

kolezko [41]

Using the Definition of Work, we have:

$T=F\DeltaS \\ 50=5F \\ \boxed {F=10N}$

If you notice any mistake in my english, please let me know, because i am not native.

3 0

3 years ago