Answer:
b. 485 kPa
Explanation:
Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:
P1T2 = P2T1
<em>P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas</em>
<em>Where P1 = 74psi</em>
<em>T2 = 20°C + 273.15 = 293.15K</em>
<em>P2 = ?</em>
<em>T1 = (95°F -32) * 5/9 + 273.15 = 308.15K</em>
<em />
Replacing:
74psi*293.15K = P2*308.15K
70.4psi
In kPa:
70.4psi * (6.895kPa / 1psi) =
<h3>b. 485 kPa
</h3>
Answer:
B. 111 J
Explanation:
The change in internal energy is the sum of the heat absorbed and the work done on the system:
ΔU = Q + W
At constant pressure, work is:
W = P ΔV
Given:
P = 0.5 atm = 50662.5 Pa
ΔV = 4 L − 2L = 2 L = 0.002 m³
Plugging in:
W = (50662.5 Pa) (0.002 m³)
W = 101.325 J
Therefore:
ΔU = 10 J + 101.325 J
ΔU = 111.325 J
Rounded to three significant figures, the change in internal energy is 111 J.
Answer:
it should be the second one since London dispersion causes interaction between molecules.
hope I helped.
Answer:
A. The person weighs 56 pounds more on Mars than on the moon
Explanation:
