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AnnZ [28]
3 years ago
15

A driver of a car traveling at 25 m/s applies the brake, causing a uniform acceleration of -3 m/s2. A) How long does it take the

car to accelerate to a final speed of 20 m/s? B) How far has the car moved during the braking period?
Physics
1 answer:
IrinaVladis [17]3 years ago
8 0
T= final velocity- initial velocity/ acceleration
T= 20m/s - 25 m/s / -3m/s^2
T= -5/ -3
T= 1.67 s
Therefore, it takes the car 1.67s to accelerate to a final speed of 20m/s.
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1) p₀ = 0.219 kg m / s, p = 0, 2)  Δp = -0.219 kg m / s, 3) 100%

Explanation:

For the first part, which is speed just before the crash, we can use energy conservation

Initial. Highest point

            Em₀ = U = mg y

Final. Low point just before the crash

           Emf = K = ½ m v²

          Em₀ = Emf

          m g y = ½ m v²

           v = √ 2 g y

Let's calculate

           v = √ (2 9.8 0.05)

           v = 0.99 m / s

1) the moment before the crash is

           p₀ = m v

           p₀ = 0.221 0.99

           p₀ = 0.219 kg m / s

After the collision, the car's speed is zero, so its moment is zero.

           p = 0

2) change of momentum

           Δp = p - p₀

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3) the reason is

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In percentage form it is 100%

3 0
4 years ago
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