1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ale4655 [162]
1 year ago
15

In the molecule represented by the chemical formula H2SO4, there would be...Select one:a. 1 hydrogen atom.b. 2 hydrogen atoms.c.

2 sulfur atoms.d. 4 sulfur atoms.
Chemistry
1 answer:
REY [17]1 year ago
3 0
<h2>Answer:</h2>

2 hydrogen atoms.

<h2>Explanations:</h2>

Given the chemical formula H2SO4,

The compound shows that the formula has 4 atoms of oxygen, one atom of sulfur and 2 hydrogen atoms.

Therefore, the number of hydrogen atom in the molecule H2SO4 is 2 hydrogen atoms.

You might be interested in
2 Points
Ganezh [65]

Answer: The answer is A. A conductor that allows electricity to flow easily

4 0
3 years ago
Whats the name?!?!?!??!?!?!?!?!?!?!!?!?!?!??!?!?!?!
SIZIF [17.4K]
Hydrogen i suppose is the right one
7 0
3 years ago
Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to
valina [46]

5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.

<u>Explanation</u>:

  • Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:

                        Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃

  • From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of  H₂SO₄.
  • Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and                                Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
  • To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is =  5.451 X 10³ kg.

 

5 0
3 years ago
How many grams of ca are needed to react completely with 2.20 L of a 4.50 m hcl solution
Dmitry_Shevchenko [17]
Ca + 2HCl = CaCl₂ + H₂

c=4.50 mol/l
v=2.20 l

n(HCl)=cv

m(Ca)/M(Ca)=n(HCl)/2

m(Ca)=M(Ca)cv/2

m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g

198 grams of Ca are needed

5 0
3 years ago
Read 2 more answers
The temperature of a substance _______ as its heat of fusion is added to melt the substance. A. increases B. remains constant C.
Alexeev081 [22]
The answer would be B. remains constant.
6 0
3 years ago
Read 2 more answers
Other questions:
  • Which is the greater distance 50 miles or 100 kilometers
    13·1 answer
  • 500.0 ml of 0.110 m naoh is added to 535 ml of 0.250 m weak acid (ka = 6.37 × 10-5. what is the ph of the resulting buffer?
    10·1 answer
  • PLEASEEE HELP!!
    13·1 answer
  • What is the molality of a solution containing 8.0 grams of solute in 0.50 kg of solvent?
    9·2 answers
  • In order to jave 2.2 moles of potassium oxide, how many grams of potassium are needed
    15·1 answer
  • What happened to a liquid when it releases enough energy
    6·2 answers
  • What is a example of eukaryote
    6·2 answers
  • Why is oxygen crucial to living things?
    10·1 answer
  • A b or c<br><br> hurry please!!
    10·2 answers
  • 4 Na + O2 → 2 Na2O<br><br> 6.79 moles of O2 will react to form how many moles of Na2O?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!