Answer:
A. 0.225 mole of H₂
B. 0.113 mole of O₂.
Explanation:
We'll begin by calculating the number of mole in 4.05 g of water (H₂O). This can be obtained as follow:
Mass of H₂O = 4.05 g
Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol
Mole of H₂O =?
Mole = mass /Molar mass
Mole of H₂O = 4.05 / 18
Mole of H₂O = 0.225 mole
Next, the balanced equation.
2H₂O —> 2H₂ + O₂
From the balanced equation above,
2 moles of H₂O produced 2 moles of H₂ and 1 mole of O₂.
A. Determination of the number of mole hydrogen produced.
From the balanced equation above,
2 moles of H₂O produced 2 moles of H₂.
Therefore, 0.225 mole of H₂O will also produce 0.225 mole of H₂.
B. Determination of the number of mole oxygen produced.
From the balanced equation above,
2 moles of H₂O produced 1 mole of O₂.
Therefore, 0.225 mole of H₂O will produce = (0.225 × 1)/2 = 0.113 mole of O₂.
Thus, 0.113 mole of O₂ is produced.
Answer:
Here's what I get
Explanation:
Ethylamine has an N atom with a lone pair of electrons.
It can act as a Brønsted-Lowry base and accept a proton from water and become an ethylammonium ion.
The structure of the ion is shown below (there is a C atom at each of the four-way bond intersections).
Answer:
How to convert volts to electron-volts
How to convert electrical voltage in volts (V) to energy in electron-volts (eV).
You can calculate electron-volts from volts and elementary charge or coulombs, but you can't convert volts to electron-volts since volt and electron-volt units represent different quantities.
Volts to eV calculation with elementary charge
The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electric charge Q in elementary charge or proton/electron charge (e):
E(eV) = V(V) × Q(e)
The elementary charge is the electric charge of 1 electron with the e symbol.
So
electronvolt = volt × elementary charge
or
eV = V × e
Example
What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 40 electron charges?
E = 20V × 40e = 800eV
Volts to eV calculation with coulombs
The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C) divided by 1.602176565×10-19:
E(eV) = V(V) × Q(C) / 1.602176565×10-19
So
electronvolt = volt × coulomb / 1.602176565×10-19
or
eV = V × C / 1.602176565×10-19
Example
What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 2 coulombs?
E = 20V × 2C / 1.602176565×10-19 = 2.4966×1020eV
Explanation:
Answer:
0.052 M
0.059 m
Explanation:
There is some missing info. I think this is the complete question.
<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>
Step 1: Calculate the moles of glucose (solute)
The molar mass of glucose is 180.16 g/mol.
4.6 g × 1 mol/180.16 g = 0.026 mol
Step 2: Calculate the molarity of the solution
0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.
M = moles of solute / liters of solution
M = 0.026 mol / 0.500 L = 0.052 M
Step 3: Calculate the mass corresponding to 500 mL of the solvent
The solvent has a density of 0.87 g/mL.
500 mL × 0.87 g/mL = 435 g = 0.44 kg
Step 4: Calculate the molality of the solution
We will use the definition of molality.
m = moles of solute / kilograms of solvent
m = 0.026 mol / 0.44 kg = 0.059 m
