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igomit [66]
1 year ago
12

What are the factors affecting qualitative analysis in chemistry​

Chemistry
1 answer:
Kitty [74]1 year ago
5 0

Answer:

Techniques and Tests

Qualitative analysis typically measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation.

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What type of reaction occurs when complex compounds are broken down into simpler substances?
Zarrin [17]
Complex compounds are broken down to simpler substances in catabolic reactions.

These kinds of reactions often occur in biological systems. In living organisms, complex compounds like lipids, proteins and complex sugar like cellulose are broken down into simpler forms. Products of these reactions are simple sugars, amino acids etc. but a certain amount of energy is also produced and stored in energy molecules for future use.
4 0
3 years ago
Rain washing away soil from a hillside
Aneli [31]

Answer:

deposition

Explanation:

8 0
2 years ago
2<br> CuCl2 +4KI -&gt; 2 Cul + 4 KCI + 12
Amanda [17]

Answer:

Explanation:

This is an example of a limiting reactant question, and is very common as a general chemistry problem.

We first see the balanced equation, that is:

2CuCl2+4KI→2CuI+4KCl+I2

We first need to find the limiting reactant

We see that 0.56 g of copper(II) chloride (CuCl2) reacts with 0.64 g of potassium iodide (KI) . So, let's convert those amounts into moles.

Copper(II) chloride has a molar mass of

134.45 g/mol . So in 0.56 g of copper(II) chloride, then there exist

0.56g134.45g/mol≈4.17⋅10−3 mol

Potassium iodide has a molar mass of

166 g/mol . So, in 0.64 g of potassium iodide, there exist

if it wrong i am sorry

5 0
3 years ago
Which of the following statements about energy is true? I. Kinetic energy cannot be transformed into another type of energy. II.
Aleks [24]

Answer:

B

Explanation:

First Law of thermodynamics says energy of the universe is constant and can only be changed in other forms of energy

5 0
3 years ago
Question a chemist mixes 35 milliliters of a solution that is 18% acid with 90 milliliters of a solution that is 68% acid. answe
Allushta [10]
Missing questions: 
<span>a) How many milliliters of acid are in the resulting mixture?
b) What percentage of the resulting mixture is acid?
a) V</span>₁ = 35 ml.
ω₁ = 18% = 0,18.
V₂ = 90 ml.
ω₂ = 68% = 0,68.
V(acid) = V₁ · ω₁ + V₂ · ω₂.
V(acid) = 35 ml · 0,18 + 90 ml · 0,68 = 67,5ml.
b) ω(acid) = 67,5 ml ÷ (35 ml + 90 ml).
ω(acid) = 54%.
8 0
3 years ago
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