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3 years ago

What determines the speed at which of a matter moves?

Physics

2 answers:

dolphi86 [110]3 years ago

6 0

Answer and Explaination:

The actual average speed of the particles depends on their mass as well as the temperature – heavier particles move more slowly than lighter ones at the same temperature. The oxygen and nitrogen molecules in air at normal room temperature are moving rapidly at between 300 to 400 metres per second.

stellarik [79]3 years ago

6 0

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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8 m/s^2. The acce

jeka94

Answer:

The maximum height will be 7408.8 meters

Explanation:

final velocity = initial velocity + acceleration × time

final velocity = 0 m/s + 58.8 m/s^2 ×6 s

Final velocity = 352.8 m/s

final velocity ^2 = initial velocity ^2 + 2 × acceleration × displacement

(352.8)^2 = (0)^2 + 2×58.8 ×displacement

Solving for displacement,

height = 1058.4 meters.

After this, the rocket is in free fall, we can use the same equation.

final velocity ^2 = initial velocity ^2 + 2 ×acceleration×displacement

final velocity = 0

0^2 = 352.8^2 + 2×(-9.8)×displacement

displacement = 6350.4 meters

the maximum height will be 7408.8 meters

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4 years ago

Tropism to stimuli could be slow at fast but all plants respond to __?

FromTheMoon [43]

HI MY NAME IS GUNTA!!!

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4 years ago

an open rectangular tank 1.0 meter wide and 2.0 meter long contains gasoline to a depth of 1.5 meters. if the height of the tank

Alekssandra [29.7K]

The maximum horizontal acceleration is solved to be 4.91 m/s^2

<u />

<h3>What is acceleration?</h3>

This is a term in physics that refers to change in velocity with time. Acceleration can be positive or negative or zero,

<u />

<u>Given data</u>

open rectangular tank

width = 1.0 m

length = 2.0 m

gasoline depth level = 1.5 m

height of the tank = 2.0 m

<h3>How to solve for maximum horizontal acceleration</h3>

lets represent the volume with x, y, and z such that z corresponds to height, y corresponds to wide or width, and x corresponds to length.

dz / dy = - ay / ( g + az )

where

ay = acceleration in the y direction

az = acceleration in the z direction which is equal to zero

g = acceleration due to gravity

plugging in az = 0

dz / dy = - ay / ( g )

ay = - ( dz / dy ) * g

to prevent spilling

dz / dy = - ( 1.5 - 1 ) / 1

dz / dy = - 0.5

ay = - ( - 0.5 ) * 9.81

ay = 4.91 meters per second square

Hence the maximum horizontal acceleration is solved to be 4.91 m/s^2

Read more on acceleration here: brainly.com/question/605631

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2 years ago

________ is a long-standing connection or bond with others.

Paul [167]

_Attachment_ is a long standing connection or bond with others

4 0

4 years ago

Read 2 more answers

Two point charges are on the y axis. A 3.90-µC charge is located at y = 1.25 cm, and a -2.4-µC charge is located at y = −1.80 cm

ladessa [460]

Answer:

a) 1.6*10^6 V

b) 13.35*10^6 V

Explanation:

The electric potential at origin is the sum of the contribution of the two charges. You use the following formula:

$V=k\frac{q_1}{r_1}+k\frac{q_2}{r_2}$ (1)

q1 = 3.90µC = 3.90*10^-6 C

q2 = -2.4µC = -2.4*10^-6 C

r1 = 1.25 cm = 0.0125 m

r2 = -1.80 cm = -0.018 m

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

You replace all the parameters in the equation (1):

$V=k[\frac{q_1}{r_1}+\frac{q_2}{r_2}]\\\\V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0125m}+\frac{-2.4*10^{-6}C}{0.018m}]=1.6*10^6V$

hence, the total electric potential is approximately 1.6*10^6 V

b) For the coordinate (1.50 cm , 0) = (0.015 m, 0) you have:

r1 = 0.0150m - 0.0125m = 0.0025m

r2= 0.015m + 0.018m = 0.033m

Then, you replace in the equation (1):

$V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0025m}+\frac{-2.4*10^{-6}C}{0.033m}]=13.35*10^6V$

hence, for y = 1.50cm you obtain V = 13.35*10^6 V

4 0

3 years ago