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Vedmedyk [2.9K]
3 years ago
10

Which law is described by saying that when the pressure of a gas in a sealed container is cut in half, the gas will double in vo

lume at a steady temperature?
Boyle’s law
Charles’s law
Dalton’s law
Gay-Lussac’s law
Chemistry
2 answers:
nadezda [96]3 years ago
7 0

Answer: The correct answer is Boyle's law.

Explanation:

Boyle's law states that 'the pressure of the gas is inversely proportional to the volume occupied by the gas at constant temperature'.

P\propto \frac{1}{V}

PV=constant or P_1V_1=P_2V_2

According to question, pressure is reduced to half of its original value by which volume of gas will get doubled of its initial value.Hence following Boyle's law.

Anon25 [30]3 years ago
4 0

I believe it would be Boyle's Law

(P [is proportional to] 1/V)

P being pressure

V being volume

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If 6 moles of sugar was added to a kilogram of water, the new boiling point would be _____ degrees C.
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Using the equation for boiling point elevation Δt
     Δt = i Kb m 
we can find the new boiling point T for the solution:
     Δt = T - 100∘C 
since we know that pure water boils at 100 °C.

We know that the van't Hoff Factor i is equal to 1 because sugar does not dissociate in water.

Also, the value of Ebullioscopic constant Kb for water is listed as 0.512 °C·kg/mol.

The molality m of the solution of 6 moles of sugar dissolved in a kilogram of water can be calculated as 
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Therefore the new boiling point T would be
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     T = i Kb m + 100 °C.
        = (1) (0.512 °C·kg/mol) (6 mol/kg) + 100 °C
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3 0
3 years ago
Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

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3 years ago
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Explanation:

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For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

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Answer:

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We are given;

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Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

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