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Vedmedyk [2.9K]
3 years ago
10

Which law is described by saying that when the pressure of a gas in a sealed container is cut in half, the gas will double in vo

lume at a steady temperature?
Boyle’s law
Charles’s law
Dalton’s law
Gay-Lussac’s law
Chemistry
2 answers:
nadezda [96]3 years ago
7 0

Answer: The correct answer is Boyle's law.

Explanation:

Boyle's law states that 'the pressure of the gas is inversely proportional to the volume occupied by the gas at constant temperature'.

P\propto \frac{1}{V}

PV=constant or P_1V_1=P_2V_2

According to question, pressure is reduced to half of its original value by which volume of gas will get doubled of its initial value.Hence following Boyle's law.

Anon25 [30]3 years ago
4 0

I believe it would be Boyle's Law

(P [is proportional to] 1/V)

P being pressure

V being volume

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If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
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Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

KBr (aq) → K+ (aq) + Br- (aq)

K2Cr2O7 (aq) → 2K+ (aq) + Cr2O7 2- (aq)

According to these balanced equations when 1 mole of KBr dissociates, it generates 1 mole of potassium ions. Following the same thought, when 1 mole of K2Cr2O7 dissociates, we obtain 2 moles of potassium ions instead.

Having said that, we calculate the moles of potassium ions coming from the KBr solution:

0.19 M KBr: this means that we have 0.19 moles of KBr in 1000 mL solution. So:

1000 mL solution ----- 0.19 moles of KBr

253 mL solution ----- x = 0.04807 moles of KBr

As we said before, 1 mole of KBr will contribute with 1 mole of K+, so at the moment we have 0.04807 moles of K+.

Now, we are told that the final concentration of K+ is 0.846 M. This means we have 0.846 moles of K+ in 1000 mL solution. Considering that volumes are additive, we calculate the amount of K+ moles we have in the final volume solution (441 mL + 253 mL = 694 mL):

1000 mL solution ----- 0.846 moles K+

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If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

2 K+ moles ----- 1 K2Cr2O7 mole

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441 mL ----- 0.269527 K2Cr2O7 moles

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