Answer: 2 : 1
Explanation:
Cation :
Ca - calcium = atomic number = 20
Electron dot configuration : 2, 8, 8, 2
Ca losses 2 electrons in its outermost shell and thus has a charge of 2+ in other to attain a stable octet state.
Anion:
F - has 7 valence electrons and thus needs 1 electron to achieve a stable octet state, hence it accepts one electron has has a charge of (-1)
Therefore,
Ratio of cation (+) to negative (-) = 2 :1
Barium forms cation : Ba²⁺
<h3>Further explanation</h3>
Given
Barium element
Required
Ion type
Solution
Barium with the symbol Ba is an alkaline earth metal element having the atomic number 56
Electron configuration of Barium: [Xe] 6s2
If we look at this configuration, then Barium will try to achieve stability by removing 2 electrons so that the electron configuration is the same as the noble gas Xenon (Xe)
Because it removes 2 electrons, Barium has the number of protons> the number of electrons so that the charge is positive and forms a cation
The electron that have the most energy in an atom is
electrons in the outer most shell
<u><em> Explanation</em></u>
Electrons in the outer shell have higher energy and they travel fur from the nucleus than those in the inner shells.
As the electrons move away form the nucleus its energy become less and less negative, that is their energy increases.
Answer:
The answer to your question is: 82.9 %
Explanation:
Data
H2 = 42.6 g
NH3 = 200 g
percent yield = ?
Reaction
3H2 + N2 ⇒ 2NH3
Process
6 g of H --------------- 34 g of N
42.6 g ------------- x
x = 241.4 g of NH3
percent yield = 200 / 241.4 x 100
= 82.9 %
Answer:
3A + B → C + 2D
Explanation:
Recall that:

So;

From the above table given in the question; we can have the following table:
Run moles of A moles of B Limiting reagent
1 0.5× 10⁻² 0.5× 10⁻² A and B are equal
2 1.0 0.5× 10⁻² 0.5× 10⁻² A
3. 1.5× 10⁻² 0.5× 10⁻² A
4 2.0× 10⁻² 0.5× 10⁻² B
Also, provided that the stoichiometric coefficients for C and D = 1 & 2 respectively.
Then, the stiochiometric ratio for A:B = 

Thus, the balanced equation is:
3A + B → C + 2D