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IrinaK [193]
1 year ago
5

Butane is a common fuel used in cigarette lighters and camping stoves. Normally supplied in metal containers under pressure, the

fuel exists as a mixture of liquid and gas, so high temperatures may cause the container to explode. At 25.08C, the vapor pressure of butane is 2.3 atm. What is the pressure in the container at 135°C (ΔH°vap ) = 24.3 kJ/mol?
Chemistry
1 answer:
klasskru [66]1 year ago
6 0

Pressure of Butane in the container at 135°C = 1.07 atm

Given:

The H°vap of butane is 24.3 kJ/mol.

starting out at 25 °C

Temperature at the end: 135 °C

2.3 atm of pressure

To Find:

The container's pressure

The perpendicular force per unit area, also known as the stress at a point within a confined fluid, is known as pressure in the physical sciences.

Equation of Clausius-Clapeyron

P2 = 1.07 atm and ln (P2/2.3 atm)

= - 24.3*110/8.31

The pressure in the container at 135°C (ΔH°vap ) is 1.07 atm

Learn more about Pressure here:

brainly.com/question/25736513

#SPJ4

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2 years ago
How many grams of water are produced from the decomposition of 63 grams of lithium hydroxide
Ymorist [56]

Answer:

18.65004 grams H2O

Explanation:

First, we need to write down the balanced chemical equation for the decomposition reaction:

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The amu of LiOH is 23.947.

The given grams of LiOH is 63.. To convert to moles, we will divide 63 by 23.947..

This gives us 2.6310 moles LiOH..

To convert to moles of H2O (and later grams of H2O), we will use the mole fractions from the balanced equation...

When we look at the balanced equation we can see that 2 moles of LIOH can produce 1 mol of Water, so:

2.6310 moles * \frac{1 molH_{2}O}{2 mol LiOH} = 1.3155 moles H2O

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3 0
2 years ago
Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced
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Mole ratio:

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2 moles KOH ---------------- 1 mole Mg(OH)₂
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= 448 g of KOH 

hope this helps!

3 0
3 years ago
Read 2 more answers
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