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4 years ago

if we are made of stardust, does that make you feel more or less important as an individual (or just the same), and why?

1 answer:

7 0

We Are Stardust—Literally. In this infrared image, stellar winds from a giant star cause interstellar dust to form ripples. There's a whole lot of dust—which contains oxygen, carbon, iron, nickel, and all the other elements—out there, and eventually some of it finds its way into our bodies.

You might be interested in

How much energy is evolved during the reaction of 51.2 g of al, according to the reaction below? assume that there is excess fe2

sesenic [268]

Answer : The amount of energy evolved during the reaction is, $-807.696KJ$ .

Solution : Given,

$\Delta H=-852KJ$

Mass of Al = 51.2 g

Molar mass of Al = 27 g/mole

First we have to calculate the moles of Al.

$\text{ Moles of Al}=\frac{\text{ Mass of Al}}{\text{ Molar mass of Al}}=\frac{51.2g}{27g/mole}=1.896moles$

The balanced combustion reaction is,

$Fe_2O_3+2Al\rightarrow Al_2O_3+2Fe$

From the given reaction, we conclude that

As, 2 moles of Al evolved energy = $-852KJ$

So, 1.896 moles of Al evolved energy = $\frac{-852KJ}{2moles}\times 1.896moles=-807.696KJ$

Therefore, the amount of energy evolved during the reaction is, $-807.696KJ$ .

8 0

3 years ago

At the end of β-oxidation all carbons of a fatty acid are released in the form of

user100 [1]

Answer:

ACETYL-CoA, FADH

2 NADH

acetyl-CoA

Explanation: Beta oxidation of carbons of fatty acid acid molecules leads to the formation Acetyl-CoA, FADH and NADH.

The overall reaction for the process

Cn-acyl-CoA + FAD + NAD+

+ H

2O + CoA → Cn-2-acyl-CoA + FADH

2 + NADH + H+

+ acetyl-CoA.

formula of NADH is C21H27N7O14P2

formula of FADH is ‎C27H35N9O15P2.

Both NADH(Nicotinamide adenine dinucleotide) and FADH( Flavin adenine dinucleotide) are

formular for Acetyl CoA IS C23H38N7O17P3S.

Beta oxidation is a breakdown process taking place in living systems which catabolises the fatty acids through glycolysis or fermentation leading to the release of Acetyl CoA, NADH AND FADH2.

4 0

3 years ago

Will mark you brainliest and give you 15 points!!

Dafna1 [17]

Answer:

Explanation:

22.4 L is the same as 1 mol.

Diatomic nitrogen has a formula mass of 28.01 g/mol, so the answer is d.

7 0

2 years ago

PLS HELPPPP

Nady [450]

Answer:

1. First one is true : as per periodic table down the group , the elements has increasing order of shell & with that the London dispersion forces brings the inter-molecules close together and bromine converted into liquid .

2. second one is False because carbon-carbon bonds are not weak bonds they form mutual covalent bonds which are stronger bonds and cannot be easily disrupted .

3. A single carbon atom has the valency of 4 so it can be bonded with four hydrogen atom at the same time .

Explanation:

5 0

4 years ago

Nicotine, a component of tobacco, is composed of c, h, and n. a 4.200-mg sample of nicotine was combusted, producing 11.394 mg o

Rudiy27

Answer:

Empirical Formula = C₅H₇N₁

Solution:

Data Given:

Mass of Nicotine = 4.20 mg = 0.0042 g

Mass of CO₂ = 11.394 mg = 0.011394 g

Mass of H₂O = 3.266 mg = 0.003266 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.011394 ÷ 0.0042) × (12 ÷ 44) × 100

%C = (2.7128) × (12 ÷ 44) × 100

%C = 2.7128 × 0.2727 × 100

%C = 73.979 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.003266 ÷ 0.0042) × (2.02 ÷ 18.02) × 100

%H = (0.7776) × (2.02 ÷ 18.02) × 100

%H = 0.7776 × 0.1120 × 100

%H = 8.709 %

%N = 100% - (%C + %H)

%N = 100% - (73.979 % + 8.709%)

%N = 100% - 82.688%

%N = 17.312 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 73.979 ÷ 12.01

Moles of C = 6.1597 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 8.709 ÷ 1.01

Moles of H = 8.6227 mol

Moles of N = %N ÷ At.Mass of O

Moles of N = 17.312 ÷ 14.01

Moles of N = 1.2356 mol

Step 3: Find out mole ratio and simplify it;

C H N

6.1597 8.6227 1.2356

6.1597/1.2356 8.6227/1.2356 1.2356/1.2356

4.985 6.978 1

≈ 5 ≈ 7 1

Result:

Empirical Formula = C₅H₇N₁

6 0

3 years ago