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faust18 [17]
3 years ago
12

The ozone layer is an important component of Earth’s atmosphere because it helps to block UV radiation from reaching Earth. The

ozone layer absorbs most of the harmful UV radiation from the Sun and stores it as heat within the stratosphere. If the ozone layer were completely removed, what effect would that change have on temperature?
The temperature would remain unchanged.
The temperature of Earth would increase.
The temperature of the upper atmospheric layers would decrease.
The temperature of Earth would decrease.
The temperature of the stratosphere would decrease.
THERE ARE MULTIPLE ANSWERS
Physics
2 answers:
kolbaska11 [484]3 years ago
3 0
The temperature on the Earth would increase.

The temperature of the stratosphere would decrease.
emmainna [20.7K]3 years ago
3 0

Answer:

The temperature on the Earth would increase.

The temperature of the stratosphere would decrease.

You might be interested in
What is Newton’s second law of motion
ddd [48]

"<em>F = dP/dt. </em> The net force acting on an object is equal to the rate at which its momentum changes."

These days, we break up "the rate at which momentum changes" into its units, and then re-combine them in a slightly different way.  So the way WE express and use the 2nd law of motion is

"<em>F = m·A.</em>  The net force on an object is equal to the product of the object's mass and its acceleration."

The two statements say exactly the same thing. You can take either one and work out the other one from it, just by working with the units.

8 0
3 years ago
Read 2 more answers
The​ half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su
neonofarm [45]

Answer:

(a) N=19\times e^{-\lambda t}

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

\lambda =\frac {0.6931}{T}

The equation of radioactivity used here is given by

N=N_{o}e^{-\lambda t}

N=19\times e^{-\lambda t}

(b) N = 8 gram

Substitute the values in above equation

\lambda =\frac {0.6931}{12}

λ = 0.0577 per hour

So, 8=19\times e^{-0.577t}

e^{-0.0577t}=0.421

Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

4 0
3 years ago
Which of the following best describes an action-reaction pair? A. The Moon Pulls on Earth, and Earth pulls back on the moon. B.
Papessa [141]
An action-reaction pair would be a pair in which one of the elements exerts a force on the other element (action), and then the other element would respond to this force by exerting another force in the opposite direction (reaction).

From the given choices, we will see that:
For choice A, the moon exerts a force on the earth by pulling it (action) and the earth responds to this force by pulling the moon (reaction in opposite direction of the action).

Therefore, the correct choice would be: 
A. <span>The Moon Pulls on Earth, and Earth pulls back on the moon.</span>
4 0
3 years ago
Read 2 more answers
A 75.0 kg diver falls from rest into a swimming pool from a height of 5.10 m. It takes 1.34 s for the diver to stop after enteri
vichka [17]

Answer:

559.5 N

Explanation:

Applying,

v² = u²+2gs............. Equation 1

Where v = final velocity,

From the question,

Given: s = 5.10 m, u = 0 m/s ( from rest)

Constant: 9.8 m/s²

Therefore,

v² = 0²+2×9.8×5.1

v² = 99.96

v = √(99.96)

v = 9.99 m/s

As the diver eneters the water,

u = 9.99 m/s, v = 0 m/s

Given: t = 1.34 s

Apply

a = (v-u)/t

a = 9.99/1.34

a = -7.46 m/s²

F = ma.............. Equation 2

Where F = force, m = mass

Given: m = 75 kg, a = -7.46 m/s²,

F = 75(-7.46)

F = -559.5 N

Hence the average force exerted on the diver is 559.5 N

7 0
2 years ago
[30 POINTS] An automobile steering wheel is shown. The ideal mechanical advantage of this wheel and axle = _____ .
mamaluj [8]

Rw/Ra = MA

18cm/2cm= MA

MA = 9

This means that Fi is 1/9 of the force applied to the axil. The distance travelled by Rw is 9 times more than Ri  is that you move 9 times more when turning the wheel using Rw.

Put more simply

Rw/Ra = Fa/Fw

  • Rw = Radius of the wheel
  • Ra = Radius of the axil
  • Fa = Force delivered on the axil
  • Fw = Force delivered by the wheel
7 0
3 years ago
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