Answer:
The correct corresponding part is;
≅
Step-by-step explanation:
The information given symbolically in the diagram are;
ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)
Segment is congruent to
(
≅
)
Segment is congruent to
(
≅
)
From which, we have;
∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∠B ≅ ∠D by CPCTC
Segment is congruent to
(
≅
) by CPCTC
Segment bisects
Segment bisects
Therefore, the correct option is ≅
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
__
The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
