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9 months ago

C. A pure substance has "one set of universal properties". What does this mean?

1 answer:

4 0

A pure substance has "one set of universal properties". This means they have some of the universal properties in common.

<h3>The definition of universal property</h3>

A characteristic that describes some structures up to an isomorphism is known as a universal property in mathematics, more specifically in category theory.

As a result, independent of the construction technique used, some objects can be described using universal properties. For example, one can define polynomial rings as derived from the field of their coefficients, rational numbers as derived from integers, real numbers as derived from integers, and rational numbers as derived from real numbers.

All of these definitions can be made in terms of universal properties. In particular, the concept of universal property offers a simple demonstration of the equality of any real number structures, requiring only that they satisfy the same universal property.

<h3>What is the universal property of all substances?</h3>

Diamagnetism is a feature that all substances share.

To learn more about Diamagnetism click on the link below:

brainly.com/question/22078990

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An unknown compound has the following chemical formula:

Softa [21]

Answer:

Formula of the compound = $P_2O_5$

Explanation:

Given,

No. of mole of O = 8.20 mol

No. of mole of P = 3.30 mol

Chemical formula = $P_2O_x$

Ratio of P and O = $\frac{2}{x}$

$\frac{2}{x} =\frac{3.3}{8.20} \\x \times 3.3 = 8.20 \times 2\\x = \frac{8.20 \times 2}{3.3} \\x=4.9969\\ = 5$

formula of the compound = $P_2O_5$

5 0

2 years ago

how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate

Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

$3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3$

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

$0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})$

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

$63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})$

= $95.7gNaClO_3$

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.

$95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})$

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0

2 years ago

Which letter corresponds with the location of f orbitals on the periodic table?

Lerok [7]

Answer:

The correct would be C i think :)

Explanation:

Stay postivie :)

8 0

2 years ago

PLEASE PLEASE HELP ME

Sav [38]

Answer:

Water

Explanation:

Water is included as a compound!

5 0

2 years ago

For a phase change, H0 = 2 kJ/mol and A S0 = 0.017 kJ/(K•mol). What are

34kurt

Answer:

ΔG = -6.5kJ/mol at 500K

Explanation:

We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:

ΔG = ΔH - TΔS

Computing the values in the problem:

ΔG = ?

ΔH = 2kJ/mol

T = 500K

And ΔS = 0.017kJ/(K•mol)

Replacing:

ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)

ΔG = 2kJ/mol - 8.5kJ/mol

8 0

2 years ago