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Nutka1998 [239]
4 years ago
11

Convection currents occur in fluids because of temperature and______ differences. Convection currents transfer ______ energy thr

oughout a fluid. They continue until all of the fluid is at the same temperature
Physics
2 answers:
navik [9.2K]4 years ago
7 0
The answer to the first blank is Density : And the second blank is thermal
Alex777 [14]4 years ago
5 0

Solution: (i) Density (ii) thermal

Liquids at lower temperatures have greater density when compared to liquids at higher temperatures.This is because, at higher temperatures, molecules have greater kinetic energy and hence they are spaced farther apart, when compared to molecules at lower temperatures. Thus, the colder layers of liquids are heavier than the warmer layers, which causes then to move down due to gravity. For the same reason, the hotter layers move upwards through the liquid.

When a liquid is heated, the molecules closest to the heat source have greater energy, their density becomes less and they move upwards. The colder layers sink downwards. The layers of the liquid which were cold initially, get heated and they travel upwards. As the process repeats, convection currents are set up in the liquid.

These currents transfer the thermal energy derived from the source throughout the liquid. The process stops when the entire liquid is at the same temperature.

Thus, convection currents occur in liquids due to temperature and <u>density</u> differences. Convection currents transfer <u>thermal</u> energy throughout a fluid.

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nexus9112 [7]
The answer would be c because a surface wave travels between two different materials, like air and water.
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3 years ago
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What is the relationship between Earth's temperature and the number of sunspots that occur?
Alexandra [31]

Answer: When there is an increased number of sun spots, it means the surface temperature is decreased which will decrease the temperature of the Earth's surface as well

Explanation:

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3 years ago
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1. The electric potential outside a living cell is higher than inside the cell by 0.073 V. How much work is done by the electric
Nostrana [21]

Answer:

ΔW = 1.168 × 10 ⁻²⁰ Joule

Explanation:

Given:

Change in Electric potential Δ V=Vout - Vin=0.073 V

Charge on sodium ions q = 1.6 ×10 ⁻¹⁹ C (+ve because of Missing one electron)

Work done by the electric fore when a sodium ions moves from outside to inside the cell is the change in the Electric potential energy Uout -Uin = ΔU  

we have

ΔW =ΔU = q ΔV

ΔW = 1.6 ×10 ⁻¹⁹ C × 0.073 V

ΔW = 1.168 × 10 ⁻²⁰ Joule

8 0
3 years ago
During most of its lifetime, s star maintains an equilibrium size in which the inward force of gravity on each atom is balanced
frez [133]

Answer:

r_f=137493m

v=8638940m/s

Explanation:

During this process the mass M=2\times10^{30}Kg will be considered constant. We start from a radius r_i=7\times10^8m and a period T_i=30\ days=(30)(24)(60)(60)s=2592000s. The final period is T_f=0.1s.

Angular momentum <em>L</em> is conserved in this process. We can use the formula L=I\omega, where I is the momentum of inertia (which for a solid sphere is I=\frac{2mr^2}{5}) and \omega=\frac{2\pi }{T} is the angular velocity, so we can write the star's angular momentum as:

L=I\omega=\frac{2mr^2}{5}\frac{2\pi }{T}=\frac{4\pi mr^2 }{5T}

Since L_f=L_i we have:

\frac{4\pi mr_f^2 }{5T_f}=\frac{4\pi mr_i^2 }{5T_i}

Which can be simplified as:

\frac{r_f^2 }{T_f}=\frac{r_i^2 }{T_i}

Which means:

r_f=\sqrt{\frac{r_i^2 T_f}{T_i}}=r_i \sqrt{\frac{T_f}{T_i}}

Which for our values is:

r_f=r_i \sqrt{\frac{T_f}{T_i}}=(7\times10^8m) \sqrt{\frac{0.1s}{2592000s}}=137493m

And we calculate the speed of a point on the equator by dividing the final circumference over the final period:

v=\frac{C_f}{T_f}=\frac{2\pi r_f}{T_f}=\frac{2\pi (137493m)}{(0.1s)}=8638940m/s

3 0
4 years ago
A heavy solid disk rotating freely and slowed only by friction applied at its outer edge takes 120 seconds to come to a stop.
alisha [4.7K]

Answer:

The time is 16 min.

Explanation:

Given that,

Time = 120 sec

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}MR^2

If the disk had twice the radius and twice the mass

The new moment of inertia

I'=\dfrac{1}{2}\times2M\times(2R)^2

I'=8I

We know,

The torque is

\tau=F\times R

We need to calculate the initial rotation acceleration

Using formula of acceleration

\alpha=\dfrac{\tau}{I}

Put the value in to the formula

\alpha=\dfrac{F\times R}{\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{MR}

We need to calculate the new rotation acceleration

Using formula of acceleration

\alpha'=\dfrac{\tau}{I'}

Put the value in to the formula

\alpha=\dfrac{F\times R}{8\times\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{8MR}

\alpha=\dfrac{\alpha}{8}

Rotation speed is same.

We need to calculate the time

Using formula angular velocity

\Omega=\omega'

\alpha\time t=\alpha'\times t'

Put the value into the formula

\alpha\times120=\dfrac{\alpha}{8}\times t'

t'=960\ sec

t'=16\ min

Hence, The time is 16 min.

5 0
3 years ago
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