Answer with Explanation:
We are given that
Mass of spring,m=3 kg
Distance moved by object,d=0.6 m
Spring constant,k=210N/m
Height,h=1.5 m
a.Work done to compress the spring initially=
b.
By conservation law of energy
Initial energy of spring=Kinetic energy of object



v=5.02 m/s
c.Work done by friction on the incline,

Answer:
It encapsulates the idea that all the particles of matter in the universe attract each other through the force of gravity – Newton's law tells us how strong that attraction is. ...
Explanation:
your answer
Answer:
The magnetic field at the center of a circular loop is
.
Explanation:
Given that,
Radius = 4.0 cm
Current = 2.0 A
We need to calculate the magnetic field at the center of a circular loop
Using formula of magnetic field

Where, I = current
r = radius
Put the value into the formula



Hence, The magnetic field at the center of a circular loop is
.
simple machine is your answer
Answer:

Explanation:
The data given in the question is
Charge : q =
Electric field Strength : E = 
Electrical potential Energy : U = 
Let, the distance be "d"
So, the formula for Electrical potential energy is

Simplified formula for distance become

Now , insert the value

or,

Rounding off
