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3 years ago

11

How fast would a 2000kg car need to be traveling to have the same momentum has a 3000kg truck driving at 18m/s?

1 answer:

Marrrta [24]3 years ago

5 0

$p = mv = 3000 * 18 = 2000 * x$

solve for x.

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The magnetic dipole moment of Earth has magnitude 8.00 1022 J/T.Assume that this is produced by charges flowing in Earth’s molte

ziro4ka [17]

Answer:

$2.08\cdot 10^9 A$

Explanation:

The magnetic dipole moment of a circular coil with a current is given by

$\mu = IA$

where

I is the current in the coil

$A=\pi r^2$ is the area enclosed by the coil, where

$r$ is the radius of the coil

So the magnetic dipole moment can be rewritten as

$\mu = I\pi r^2$ (1)

Here we can assume that the magnetic dipole moment of Earth is produced by charges flowing in Earth’s molten outer core, so by a current flowing in a circular path of radius

$r=3500 km = 3.5\cdot 10^6 m$

Here we also know that the Earth's magnetic dipole moment is

$\mu = 8.0\cdot 10^{22} J/T$

Therefore, we can re-arrange eq (1) to find the current that the charges produced:

$I=\frac{\mu}{\pi r^2}=\frac{8.00\cdot 10^{22}}{\pi (3.5\cdot 10^6)^2}=2.08\cdot 10^9 A$

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3 years ago

Why do scientists ask questions?

andrezito [222]

Scientists ask questions so that they can be answered. As well as solving the world and its mysteries

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3 years ago

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Analyze how buffers allow you to eat acidic and basic foods without changing your blood pH.

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Buffers neutralize the acid and the bases

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3 years ago

The weight of a metal bracelet is measured to be 0.10400 N in air and 0.08400 N when immersed in water. Find its density.

Anna007 [38]

Answer:

The density of the metal is 5200 kg/m³.

Explanation:

Given that,

Weight in air= 0.10400 N

Weight in water = 0.08400 N

We need to calculate the density of metal

Let $\rho_{m}$ be the density of metal and $\rho_{w}$ be the density of water is 1000kg/m³.

V is volume of solid.

The weight of metal in air is

$W =0.10400\ N$

$mg=0.10400$

$\rho V g=0.10400$

$Vg=\dfrac{0.10400}{\rho_{m}}$ .....(I)

The weight of metal in water is

Using buoyancy force

$F_{b}=0.10400-0.08400$

$F_{b}=0.02\ N$

We know that,

$F_{b}=\rho_{w} V g$ ....(I)

Put the value of $F_{b}$ in equation (I)

$\rho_{w} Vg=0.02$

Put the value of Vg in equation (II)

$\rho_{w}\times\dfrac{0.10400}{\rho_{m}}=0.02$

$1000\times\dfrac{0.10400}{0.02}=\rho_{m}$

$\rho_{m}=5200\ kg/m^3$

Hence, The density of the metal is 5200 kg/m³.

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3 years ago

When did the ball fly farther—when it hit the moving bat or the bat that did not move?

8_murik_8 [283]

Answer:

when it hit the moving bat

Explanation:

force equals mass times acceleration which means the moving bat will add more force to the ball.

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