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Andrei [34K]
3 years ago
11

What do you need to calculate the speed of sound

Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

so that at temperature C = F, the speed of sound is m/s = ft/s = mi/hr. This calculation is usually accurate enough for dry air, but for great precision one must examine the more general relationship for sound speed in gases.

Explanation:

Hyper physics .com AND BRAINLIEST WOULD BE APPRECIATED

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Since many wavelengths of light are measured in nanometers, it's useful to know that planck's constant (h) multiplied with the s
MrRa [10]

Answer:

E = h f      and since f = c / λ     we have E = h c / λ

Thus  λ = h c / E

Also, 1 ev = 1.6E-19 C

λ = 6.63E-34 * 3.0E8 / (1.6 * 1.6E-19)

λ = 6.63 * 3.0 / (1.6 * 1.6) * E-7

λ = 7.77E-7 = 777 nanometers

(B) is correct

4 0
2 years ago
If an item as a density of.63 g/mL, when placed in water the item will
sergij07 [2.7K]

Float. This is because water has a density of 1 g/ml, so anything less than this will float.

5 0
4 years ago
1. What is the equivalent resistance<br> 2. What is the current<br> 3. What is the power
tiny-mole [99]

Answer:

2

Explanation:

6 0
4 years ago
A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00 m above the ground. At th
Elis [28]

Answer:

  • <u>The water ballon that was thrown straight down at 2.00 m/s hits the ground first, 0.19 s before the other ballon.</u>

Explanation:

The motions of the two water ballons are ruled by the kinematic equations:

  • y=y_0+V_0t-gt^2/2

We are only interested in the vertical motion, so that equation is all what you need.

<u>1. Water ballon is thrown horizontally at sped 2.00 m/s.</u>

The time the ballon takes to hit the ground is independent of the horizontal speed.

Since 2.00 m/s is a horizontal speed, you take the initial vertical speed equal to 0.

Then:

y=y_0+V_0t-gt^2/2\\ \\ 0=6.00m-9.8\frac{m}{s^2} t^2/2\\ \\ t=\sqrt{2\times6.00m/9.8\frac{m}{s^2}}\\\\ t=1.11s

<u>2. Water ballon thrown straight down at 2.00 m/s</u>

Now the initial vertical speed is 2.00 m/s down. So, the equation is:

0=6.00m-2.00\frac{m}{s}t-9.8\frac{m}{s^2}t^2/2\\ \\ 4.9t^2+2t-6=0\\ \\ t=0.92s

To solve the equation you can use the quadratic formula.

t=\frac{-2+/-\sqrt{2^2-4(4.9)(-6)} }{2(4.9)}\\ \\ t=-1.33\\ \\ t=0.92

You get two times. One of the times is negative, thus it does not have physical meaning.

<u>3. Conclusion:</u>

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

5 0
3 years ago
What are some examples of uses of minerals? Select 3 choices.
julia-pushkina [17]

Answer:

salt, toothpaste, and applesauce

Explanation:

All of these have minerals in them. Hope this helps! :)

5 0
3 years ago
Read 2 more answers
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