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3 years ago

What do you need to calculate the speed of sound

Physics

1 answer:

lbvjy [14]3 years ago

4 0

Answer:

so that at temperature C = F, the speed of sound is m/s = ft/s = mi/hr. This calculation is usually accurate enough for dry air, but for great precision one must examine the more general relationship for sound speed in gases.

Explanation:

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An elevator car, with a mass of 450 kg is suspended by a single cable. At time = 0s, the elevator car is raised upward. The tens

Alexeev081 [22]

Answer:

33.33 m/s

Explanation:

m = 450 kg. T = 5000 N, t = 3 seconds,

let the net acceleration is a.

T = m a

a = 5000 / 450 = 11.11 m/s^2

u = 0 , v = ?

Let v be the velocity after 3 seconds.

Use first equation of motion

v = u + a t

v = 0 + 11.11 x 3 = 33.33 m/s

5 0

3 years ago

A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 met

andrew11 [14]

Answer: $3 m/s^2$

Explanation:

The acceleration of the motorcycle is given by

$a=\frac{v-u}{t}$

where

v=24 m/s is the final velocity of the motorcycle

u=15 m/s is the initial velocity

t=3 s is the time taken

Substituting these numbers into the equation, we find

$a=\frac{24 m/s-15 m/s}{3 s}=\frac{9 m/s}{3s}=3 m/s^2$

4 0

3 years ago

Read 2 more answers

A flutist assembles her flute in a room where the speed of sound is 342m/s . When she plays the note A, it is in perfect tune wi

USPshnik [31]

Answer:

a.3Hz

b.0.0034m

Explanation:

First, we know the flute is an open pipe, because open pipe as both end open and a close organ pipe as only one end close.

The formula relating the length and he frequency is giving as

$f=\frac{nv}{2l}\\$ .

a.we first determine the length of the flute at the fundamental frequency i.e when <em>n</em>=1 and when the speed is in the 342m/s

Hence from

$f=\frac{nv}{2l}\\\\l=\frac{342}{2*440}\\ l=0.389m\\$ .

since the value of the length will remain constant, we now use the value to determine the frequency when the air becomes hotter and the speed becomes 345m/s.

$f=\frac{nv}{2l} \\f=\frac{345}{2*0.389}\\f=443.4Hz$

Hence the require beat is

$B=/f_{1}-f_{2}/\\B=/440-443/\\B=3Hz$ .

b. since the length is dependent also on the speed and frequency, we determine the new length when she plays with a fundamental frequency when the speed of sound is 345m/s

using the formula

$L_{new}=\frac{v}{2f}\\\\L_{new}=\frac{345}{2*440}\\\\L_{new}=0.39204$