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Westkost [7]
2 years ago
9

Jane slowly paddles her canoe across a calm lake. Explain what makes the boat moves forward. What principle best explains this s

ituation?
Physics
1 answer:
nalin [4]2 years ago
7 0
Janes paddles push on the water and the water pushes back on janes paddles.

Newtons 3. Law: Action = -Reaction
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a bends each wavelength of white light slightly differently so that each wavelength color comes out separated forming a rainbow
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Projectile motion in two dimensions cannot be determined by breaking the problem into two connected one-dimensional problems.
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The answer I believe is False
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Find the dimension of density​
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Density = Mass divided by Volume
6 0
3 years ago
If a block of wood dropped from a tall building has attained a velocity of 78.4 m/s how long has it been falling
ryzh [129]

Gravity adds 9.8 m/s to the speed of a falling object every second.

An object dropped from 'rest' (v = 0) reaches the speed of 78.4 m/s after  falling for (78.4 / 9.8) = <em>8.0 seconds</em> .

<u>Note:</u>

In order to test this, you'd have to drop the object from a really high cell- tower, building, or helicopter.  After falling for 8 seconds and reaching a speed of 78.4 m/s, it has fallen 313.6 meters (1,029 feet) straight down.

The flat roof of the Aon Center . . . the 3rd highest building in Chicago, where I used to work when it was the Amoco Corporation Building . . . is 1,076 feet above the street.

5 0
3 years ago
When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Nesterboy [21]

Answer:

Explanation:

Given

Displacement is \frac{1}{3} of Amplitude

i.e. x=\frac{A}{3} , where A is maximum amplitude

Potential Energy is given by

U=\frac{1}{2}kx^2

U=\frac{1}{2}k(\frac{A}{3})^2

U=\frac{1}{18}kA^2

Total Energy of SHM is given by

T.E.=\frac{1}{2}kA^2

Total Energy=kinetic Energy+Potential Energy

K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2

K.E.=\frac{8}{18}kA^2

Potential Energy is \frac{1}{8} th of Total Energy

Kinetic Energy is \frac{8}{9} of Total Energy

(c)Kinetic Energy is 0.5\times \frac{1}{2}kA^2

P.E.=\frac{1}{4}kA^2

\frac{1}{2}kx^2=\frac{1}{4}kA^2

x=\frac{A}{\sqrt{2}}                  

7 0
3 years ago
Read 2 more answers
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