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statuscvo [17]
3 years ago
9

Robidium and cesium have similar chemical properties because in the ground it states the atoms of both elements each have

Chemistry
1 answer:
anzhelika [568]3 years ago
5 0
It would be one electron in the outermost shell. Hope this helps!
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Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
Washing machines use a large amount of water. A student suggested that old pairs of stained jeans which have to be washed more f
sukhopar [10]

Answer:

C |||| It is not practical because it takes a huge amount of water to produce a new pair of jeans

Explanation:

If you're doing flvs then it's C.

5 0
3 years ago
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Mrrafil [7]

Moles: 1

Weight, g : 192.3900

8 0
3 years ago
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Gas laws describe and predict the behavior of gases without attempting to explain why they happen
Nutka1998 [239]

The gas laws describe and predict the behavior of gases with an explanation and experimental data

So the given statement is False.

2) The volume of gas can be calculated based on Avagadro's law

It states that the volume of a gas is directly proportional or varies with the moles of the gas. Higher the moles more the volume, condition is the pressure and temperature are constants in the two conditions

Thus as here the pressure and temperature of nitrogen gas is kept constant

V α  moles

or

\frac{V1}{n1}=\frac{V2}{n2}

Where

V1 = 6 l

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V2 = ?

n2 = 0.75 mol

On putting values

V2 = 6 X 0.75 / 0.5 = 9 L

so resulting volume of the gas will be 9L

5 0
3 years ago
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Serhud [2]

Answer & Explanation:

  • The compound is considered as hydrocarbon because it contains only carbon and hydrogen.
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  • CH₃CH₂CH₃ "propane".
7 0
3 years ago
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