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2 years ago

Robidium and cesium have similar chemical properties because in the ground it states the atoms of both elements each have

Chemistry

1 answer:

anzhelika [568]2 years ago

5 0

It would be one electron in the outermost shell. Hope this helps!

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Which of the element pairs are in the same period?

Valentin [98]

Answer:

Caesium and Barium

Explanation:

Once again, if you look at the periodic table, you can see that Caesium and Barium are in the same period (Period 6).

<em>Feel free to mark this as brainliest! :D</em>

4 0

2 years ago

42.7 L to mililiters

marin [14]

42700 milliliters would be the answer...

Hope this helps!

3 0

3 years ago

Why do atoms share electrons in covalent bonds?

vladimir2022 [97]

To fill the other element's shell.

7 0

2 years ago

Read 2 more answers

If you were to remove an electron from a sodium atom that has eleven protons, what would be the electrical charge of the ion?

damaskus [11]

Answer:

positive one (+1)

Explanation:

sodium having atomic mass is twenty three (23) and atomic number is eleven (11).

Sodium atom having only one electron in it's outer most shell and it is easy for atom to lose this electron from outer most shell to make itself stable.

So after losing this electron positive charge on the upper right side of the atom will occur with the number of electron lose that is Na+1 .

4 0

3 years ago

If a hydrogen atom and a helium atom have the same kinetic energy:________

Nuetrik [128]

Answer: If a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

Explanation:

The relation between energy and wavelength is as follows.

$E = \frac{hc}{\lambda}\\$

This means that energy is inversely proportional to wavelength.

As it is given that energy of a hydrogen atom and a helium atom is same.

Let us assume that $E_{hydrogen} = E_{helium} = E'$ . Hence, relation between their wavelengths will be calculated as follows.

$E_{hydrogen} = \frac{hc}{\lambda_{hydrogen}}$ ... (1)

$E_{helium} = \frac{hc}{\lambda_{helium}}$ ... (2)

Equating the equations (1) and (2) as follows.

$E_{hydrogen} = E_{helium} = E'\\\frac{hc}{\lambda_{hydrogen}} = \frac{hc}{\lambda_{helium}} = E'\\\lambda_{helium} = \lambda_{hydrogen} = E'$

Thus, we can conclude that if a hydrogen atom and a helium atom have the same kinetic energy then the wavelength of the hydrogen atom will be roughly equal to the wavelength of the helium atom.

7 0

2 years ago