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3 years ago

What is the purpose of gears?

Engineering

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

To help wheels move in a circle

Explanation:

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A mass of 0.3 kg is suspended from a spring of stiffness 0.4 N/mm. The damping is 3.286335345 kg/s. What is the undamped natural

mina [271]

Answer:

f=5.81 Hz

Explanation:

Given that

m= 0.3 kg

K= 0.4 N/mm

K= 400 N/m

C= 3.28

We know that undamped natural frequency given as

$\omega= \sqrt{\dfrac{K}{m}}$

Now by putting the values

$\omega= \sqrt{\dfrac{K}{m}}$

$\omega= \sqrt{\dfrac{400}{0.3}}$

ω = 36.51 rad/s

We know that

ω = 2 π f

36.51 = 2 x π x f

f=5.81 Hz

So the undamped natural frequency is 5.81 Hz.

6 0

4 years ago

Imagine a cantilever beam fixed at one end with a mass = m and a length = L. If this beam is subject to an inertial force and a

harkovskaia [24]

Answer:

jsow

hfhcffnbxhdhdhdhdhdhdddhdhdgdhdhdhdhdhdhhhdhdjsksmalalaksjdhfgrgubfghhhhhhh

Explanation:

<h3>grudb</h3>

3 0

3 years ago

Someone please please help me and explain!! I will give brainliest if right!!!

Mariulka [41]

R=10+15+30

55 is the answer to the question

5 0

3 years ago

Read 2 more answers

Re armature of a 4 pole DC generator is required to generate an emf of 520v on open circuit when revolving at a speed of 660rpm.

bija089 [108]

Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.

Given the following data:

Emf = 520 Volts

Speed = 660 r.p.m

Number of armature conductors = 144 slots

Number of poles = 4 poles

Number of parallel paths = 2

To find the magnetic flux per pole:

Mathematically, the emf generated by a DC generator is given by the formula;

$E = \frac{\theta ZN}{60}$ × $\frac{P}{A}$

Where:

E is the electromotive force in the DC generator.

Z is the total number of armature conductors.

N is the speed or armature rotation in r.p.m.

P is the number of poles.

A is the number of parallel paths in armature.

Ф is the magnetic flux.

First of all, we would determine the total number of armature conductors:

$Z = 144$ × $2$ × $3$

Z = 864

Substituting the given parameters into the formula, we have;

$520 = \frac{\theta (864)(660)}{60}$ × $\frac{4}{2}$

$520 = \theta (864)(11)$ × $2$

$520 = 19008 \theta \\\\\Theta = \frac{520}{19008}$

Magnetic flux = 0.0274 Weber.

Therefore, the magnetic flux per pole is 0.0274 Weber.

5 0

3 years ago

Pls help me it’s due today

hichkok12 [17]

Answer:

C. 14.55

Explanation:

12 x 10 = 120

120 divded by 10 is 12

so now we do the left side

7 x 3 = 21 divded by 10 is 2

so now we have 14

and the remaning area is 0.55

so 14.55

6 0

3 years ago