Well i think it 120 your welcome
Answer:
![r=\sqrt[3]{\frac{3v}{4} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3v%7D%7B4%7D%20%7D)
Step-by-step explanation:
To solve for
:
(given)
(times
on both sides)
![r=\sqrt[3]{\frac{3v}{4} }](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3v%7D%7B4%7D%20%7D)
I hope this helps :)
Answer: 100+10+1
You basically place zeroes instead of the actual digit to find the value of each number.
Example:
855
800+50+5
Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is
552
Answer:
-88
Step-by-step explanation:
Let N(x) be the number of students at NMS for a certain number of years.
Let S(x) be the number of students at SMS for a certain number of years.
Let x be the number of years.
N(x)=1240-25x
S(x)=800-30x
When # of students is equal, N(x)=S(x). Therefore, we are looking for the value of x (# of years) when 1240-25x=800-30x
Subtract 1240 from each side
-25x=-440-30x
Add 30x
5x=-400
x=-88 years
Check your numbers.