Answer:
What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Explanation:
The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Answer:
The focal length of the objective is L/20.
Explanation:
Given that,
Magnification of the standard biological microscope, m = 200
Let the magnification of the eyepiece is, 
Let 
is the magnification of objective lens. The formula of the magnification is given by :
The formula of the magnification is given by :
L is length of microscope
is focal length of the objective
So, the focal length of the objective is L/20.
In a level cruise on a passenger airliner, flying in a straight line at a steady 550 miles per hour.
Acceleration is zero.
The values in figure 1 shows h1 = 39 m, h2 = 13 m, h3 =
25 with a speed of 1.5m/s
The Initial speed u = 1.5m/s.
Vertical distance covered between point 1 and point 2 is
(39-13) =26m
The expanse 45 m is equal to a height of (45/6) =7.5 (As
frictional force is mg/6)
With the kinematics equation v^2 =u^2 + 2as
V^2 = 1.5^2 + 2*9.8 (26 + 7.5)
V = 25.7 m/s
