Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:
where
f is the frequency
T is the period
In this problem, we have
so, the frequency of the waveform is
And by converting into kiloHertz,
By angular speed, the frequency is 2.39 Hz.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2πf
Hence,
ω² = k / m
(2πf)² = k / m
k = (2πf)² / m
where f is frequency.
From the question above, we know that:
m1 = 0.6 kg
f1 = 3 Hz
m2 = 0.38 kg
The spring is same, hence the spring constant is the same
k1 = k2
(2πf1)² / m1 = (2πf2)² / m2
f1² / m1 = f2² / m2
3² / 0.6 = f2² / 0.38
f2² = 5.7
f2 = 2.39 Hz
Find more on angular speed at: brainly.com/question/6860269
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When you learn something mew that trumps what you already knew
Answer:
k = 5.71 N/m
Explanation:
k = F/Δx = 20.0/3.50 = 5.71 N/m which is almost nothing as far as a spring goes.
Generally, the electromagnetic spectrum diagram is represented using two variables: the frequency of the wave and the wavelength of the wave. Since there is an inverse proportionality between the two variables, it means that the higher the frequency, the smaller the wavelength (and viceversa), so when they are put together in the diagram their scales go into opposite directions.