(a) 2 Hz
The frequency of the nth-harmonic is given by

where
is the fundamental frequency
Therefore, the frequency of the third harmonic of the A (
) is

while the frequency of the second harmonic of the E (
) is

So the frequency difference is

(b) 2 Hz
The beat frequency between two harmonics of different frequencies f, f' is given by

In this case, when the strings are properly tuned, we have
- Frequency of the 3rd harmonic of A-note: 1320 Hz
- Frequency of the 2nd harmonic of E-note: 1318 Hz
So, the beat frequency should be (if the strings are properly tuned)

(c) 1324 Hz
The fundamental frequency on a string is proportional to the square root of the tension in the string:

this means that by tightening the string (increasing the tension), will increase the fundamental frequency also*, and therefore will increase also the frequency of the 2nd harmonic.
In this situation, the beat frequency is 4 Hz (four beats per second):

And since the beat frequency is equal to the absolute value of the difference between the 3rd harmonic of the A-note and the 2nd harmonic of the E-note,

and
, we have two possible solutions for
:

However, we said that increasing the tension will increase also the frequency of the harmonics (*), therefore the correct frequency in this case will be
1324 Hz