1) Horizontal velocity, Vx
Vx is constant and equal to 5.0 m/s
The graph Vx(t) = 5.0 m/s is a horizontal line (parallel to the horizontal t-axis). that intercepts the vertical-axis at 5.0 and runs from t = 0 to t = 2.
2) Vertical velocity, Vy
Vy = gt = 10t
d = at^2 / 2 => tmax = √(2d / a) = √(2*20m/10m/s^2) = 2 s
Graph Vy is an inclined line with slope 10 m/s^2, that runs from t =0 to t = 2 s, and passes through the points (0,0), (1,10), and (2,20).
Answer:
4.266 m.
Explanation:
Given,
Speed of the electron = 7.50 x 10⁶ m/s
Magnetic field, B = 1 x 10⁻⁵ T
radius of circular path = ?
Using formula of radius of curvature of the charge particle
m is mass of electron
q is charge of electron
r = 4.266 m
Hence, radius of circular path is equal to 4.266 m.
Whenever an object is in projectile motion, that is, it has 2-dimensional motion in the x and y axis, the resultant force on the object is in the y-direction.
This is because once the object has been projected, or the ball has been kicked in this case, there is no longer a force being applied on it in the x-direction. The air resistance is also neglected so the ball's final velocity in the x-direction is equal to its initial velocity in the x-direction.
However, the force of gravity cannot be neglected and causes the ball to come downwards. Therefore, after the ball has been projected, the net force on the ball is downwards, due to gravity.
Take a look at a simple reaction like the one below:
In this reaction some reactant A is turned into some product B. The rate of reaction can be represented by a decrease in concentration of A over time or as the increase of B over time. This is written:
A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power...
Solution,
displacement = 20 m
time = 10 sec
force = 500 N
work done = ?
power = ?
Now ,
work done = f × s
= 500 N × 20 m
= 10000 j
Now ,
~nightmare 5474~
