Answer:
No, if a car is going faster. The RPM is obviously higher. If that is higher, you can burn through gas and energy much faster. A car going at 15mph would be cruising and wouldn't have to worry too much about burning our your vehicle.
Explanation:
Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's angular speed M and tangential speed vM is mathematically given as
Mary's and Alex's angular speed=1.43
Tangential speed mary=3.22 m/s
Tangential speed alex =2.260m/s
<h3>What is Mary's and Alex's angular
speed M and tangential speed vM?</h3>
Generally, the equation for angular speed is mathematically given as

w = 1.61 rev/see 3.9
Centripetal acc mary = v^2/r
Centripetal acc mary = w^2r
Centripetal acc mary = w^2x 2m
Centripetal acc. of Alex = w²x L.u
Therefore

Hence
tang. speed V=Wr
tang. speed of mary = 1.61x2 = 3.22 m/s
tang. speed of Alex: 1.61X1·4 =2.260m/s
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Answer:
3.28 m
3.28 s
Explanation:
We can adopt a system of reference with an axis along the incline, the origin being at the position of the girl and the positive X axis going up slope.
Then we know that the ball is subject to a constant acceleration of 0.25*g (2.45 m/s^2) pointing down slope. Since the acceleration is constant we can use the equation for constant acceleration:
X(t) = X0 + V0 * t + 1/2 * a * t^2
X0 = 0
V0 = 4 m/s
a = -2.45 m/s^2 (because the acceleration is down slope)
Then:
X(t) = 4*t - 1.22*t^2
And the equation for speed is:
V(t) = V0 + a * t
V(t) = 4 - 2.45 * t
If we equate this to zero we can find the moment where it stops and begins rolling down, that will be the highest point:
0 = 4 - 2.45 * t
4 = 2.45 * t
t = 1.63 s
Replacing that time on the position equation:
X(1.63) = 4 * 1.63 - 1.22 * 1.63^2 = 3.28 m
To find the time it will take to return we equate the position equation to zero:
0 = 4 * t - 1.22 * t^2
Since this is a quadratic equation it will have to answers, one will be the moment the ball was released (t = 0), the other will eb the moment when it returns:
0 = t * (4 - 1.22*t)
t1 = 0
0 = 4 - 1.22*t2
1.22 * t2 = 4
t2 = 3.28 s
Answer:
Gravitational force mg' =(49)mg=49×63=28N.
Explanation:
What is the gravitational force on it due to the Earth , at a height equal to half the radius of the Earth ? (Given that the radius of Earth = 6400 km). Gravitational force mg ( This is not the real explanation)
Answer:
B. equals zero
Explanation:
Given data
one complete cycle = heat flow
solution
we have given that when heat engine complete 1 cycle change in energy = net heat flow
that is always equal to zero
from first law of thermodynamics that
ΔU = Q + W
we know ΔU is the change internal energy in system and Q is net heat transfer in system and W is net work done in system
therefore change of internal energy during one cycle
ΔU = Ufinal - Uinitial
ΔU = Uinitial - Uinitial = 0