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shusha [124]
3 years ago
6

A bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes.

What is the smallest insect a bat can detect? Assume that bats emit a chirp at a frequency of 47.6 kHz, and that the speed of sound in air is 413 m/s. Answer in units of mm.
Physics
1 answer:
zaharov [31]3 years ago
3 0

Given that,

Frequency emitted by the bat, f = 47.6 kHz

The speed off sound in air, v = 413 m/s

We need to find the wavelength detected by the bat. The speed of a wave is given by formula as follows :

v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{413}{47.6\times 10^3}\\\\\lambda=0.00867\ m

or

\lambda=8.67\ mm

So, the bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes i.e. 8.67 mm.

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A person travelled in the -x direction at a constant speed of 2.5 m/s. The person's final position is -10.0 m, and the initial p
Nostrana [21]

Answer:

(c) time required to travel = 8 sec

Explanation:

We have given the final position = -10 m on x axis

And the initial position =10 m

So total distance = 10-(-10)=20 m

The speed is given as 2.5 m/sec

We have tof ind the time required by the person to travel

Time is given by t=\frac{distance}{speed}=\frac{20}{2.5}=8 sec

So the option (c) is correct option

4 0
4 years ago
Please help, my homework is due in a couple of days and I'm stuck. A plane is travelling 10.0 meters per second (this means the
ss7ja [257]

Answer:

  • < 25 m/s
  • triangle inequality
  • between north and east
  • 45° < angle < 60°

Explanation:

(a) Just as one-dimensional numbers add on a number line by putting them end-to-end, so two-dimensional numbers add on a coordinate plane the same way.

Here, we choose to let the positive y-axis represent North, and the positive x-axis, East. This is the way a map is conventionally oriented. The velocity of the plane is represented by a vector pointing north (up). Its length represents the magnitude of the velocity. Likewise, the wind is represented by a vector of length 15 pointing east (right). The sum of these is the hypotenuse of the triangle they form.

The magnitude of the sum can be found here using the Pythagorean theorem, but for the purpose of this question, you're not asked to find that.

Instead, you're asked to estimate whether it is more or less than 25 (m/s).

Your knowledge of the triangle inequality will tell you that the hypotenuse (resultant) must be shorter than the sum of the lengths of the sides of the triangle, hence must be less than 10+15 = 25.

__

(b) The triangle inequality says the resultant is less than the sum of the other two sides of the triangle.

__

(c) Since the wind is blowing the plane toward the east, but the plane is traveling toward the north, the resulting direction is somewhere between north and east.

__

(d) "Somewhere between north and east" can be expressed as the inequality ...

  0° < angle < 90°

4 0
4 years ago
Four point charges are placed at the corners of a square. Each charge has the identical value +Q. The length of the diagonal of
kvv77 [185]

Answer:V_{net}=4\frac{kQ}{a}    

Explanation:

Given

charge on each Particle is Q

Length of diagonal of the square is 2a

therefore distance between center and each charge is \frac{2a}{2}=a

Electric Potential of charged Particle is given by

For First Charge

V_1=\frac{kQ}{a}

V_2=\frac{kQ}{a}

V_3=\frac{kQ}{a}

V_4=\frac{kQ}{a}

total Electric Potential At center is given by

V_{net}=V_1+V_2+V_3+V_4

V_{net}=4\times \frac{kQ}{a}

V_{net}=4\frac{kQ}{a}            

7 0
3 years ago
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