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Anna35 [415]
3 years ago
9

What is the overall voltage for the nonspontaneous redox reaction involving

Chemistry
2 answers:
Ann [662]3 years ago
6 0

Answer:

Answer D => E°(Mg°/Cu⁺²) = 0.34 + 2.37 = 2.71v

Explanation:

(Oxidation) =>  Mg°(s) => Mg⁺²(aq) + 2e⁻    E°(Mg°/Mg⁺²) = -2.37 v

(Reduction) => Cu⁺²(aq) + 2e⁻ => Cu°(s)     E°(Cu⁺²/Cu°) = +0.34 v

________________________________________________

Net Rxn => Mg°(s) + Cu⁺²(aq) => Mg⁺²(aq) + Cu°(s)

Std Cell Potential (25°C/1Atm) = E°(Redn) = E°(Oxidn) = +0.34v - (-2.37v)

= 0.34v + 2.37v = 2.72v

Margarita [4]3 years ago
3 0

Answer: B -2.37 -0.34

Explanation: A P E X

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Balancing means there are equal amount of molecules on each side, both reactant and products. This is a method I like to do.

Under, I count how many molecules are in each side.

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Let's guess and make the number of oxygens equal on both sides.

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See what we did there? We multiplied the MgO on the products side by 3 so we can have 3 oxygens. Now let's multiply the Mg on the reactants by three so Mg AND O can be equal.

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