Answer:
hydronium and hydroxide ions are present both in pure water and in all aqueous solutions, and their concentrations are inversely proportional as determined by the ion product of water (Kw). The concentrations of these ions in a solution are often critical determinants of the solution’s properties and the chemical behaviors of its other solutes, and specific vocabulary has been developed to describe these concentrations in relative terms. A solution is neutral if it contains equal concentrations of hydronium and hydroxide ions; acidic if it contains a greater concentration of hydronium ions than hydroxide ions; and basic if it contains a lesser concentration of hydronium ions than hydroxide ions.
Answer:
<em>Three (3) of the molecules are polar: </em>
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<em>.</em>
Explanation:
Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).
- PCl5 is <u>non-polar</u> with a symmetric geometry
- CoS is <u>polar</u>
- XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
- SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
Answer: The correct answer is Heterogeneous mixture
Explanation:
Heterogeneous mixture are those mixture in which:
- Substance is distributed in non uniform manner.
- Two distinct layers are formed
Thus when water and dirt are mixed together it results in the formation of a heterogeneous mixture and after sometimes two different layers will be observed.
Hence, in the bottle there is a heterogeneous mixture of water and dirt.
Answer:
trigonal planar
Explanation:
The molecule SO3 is of the type AX3. The molecule is symmetrical and non polar.
There are three regions of electron density in the molecule. This corresponds to a trigonal planar geometry. This means that the three oxygen atoms are arranged at the corners of a triangle. The bond angle is 120 degrees.
Answer:
The correct option is;
d 4400
Explanation:
The given parameters are;
The mass of the ice = 55 g
The Heat of Fusion = 80 cal/g
The Heat of Vaporization = 540 cal/g
The specific heat capacity of water = 1 cal/g
The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice
The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal
The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change
The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal
The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice
The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal
The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal
However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.
The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal
