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Jlenok [28]
4 years ago
7

When a 57-gram piece of aluminum at 100oC is placed in water, it loses 735 calories of heat while cooling to 30oC. Calculate the

specific health capacity of the aluminum
Physics
2 answers:
Archy [21]4 years ago
7 0

Answer:

specific heat capacity of aluminium is 0.184 Calroie/ gram-K.

Explanation:

As we know that heat transferred to a given material to change its temperature is given as

Q = ms\Delta T

here we know

Q = heat given = 735 calorie

m = mass = 57 gram

initial temperature = 100 degree C

final temperature = 30 degree C

now by above formula we will have

735 = 57(s)(100 - 30)

s = 0.184 \frac{cal}{g-K}

Tomtit [17]4 years ago
4 0
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