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3 years ago

What would happen to a nucleus containing two or more protons if the strong force was absent?

Chemistry

1 answer:

Otrada [13]3 years ago

6 0

The positively charged protons would repel one another and fly apart, destroying the nucleus.

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Which type of stoichiometric calculation does not require the use of the molar mass?

Marianna [84]

The choices can be found elsewhere and as follows:

a. mass-mass problems
b. mass-volume problems 
c. mass-particle problems 
d. volume-volume problems

I believe the correct answer is option D. It is volume-volume problems that does not require the use of molar mass. Here you are dealing with molarities and volumes to determine concentrations. Molar mass is not part of any calculations.

6 0

3 years ago

Read 2 more answers

Complete the table for ion charge based upon their losing or gaining electrons in the outer shell. (Use the periodic table as ne

PolarNik [594]

Answer:

Explanation:

Group one:

The elements of group one shows +1 charge because these all are metals and lose their one valance electron.

Hydrogen lithium sodium potassium rubidium cesium francium

Group 2:

The elements of group two shows +2 charge because these all alkali metals and lose their two valance electrons.

beryllium magnesium calcium strontium barium radium

Group 3:

The elements of group three-B shoes +3 charge by losing three valance electrons.

Scandium yttrium lanthanum actinium

Group 4:

The elements of group 4th A and 4th B lose four electrons or gain four electrons to complete the octet and shows +4 or -4 charge.

Group 5:

Group 5th elements gain three electrons and shows -3 charge to complete the 8 electrons. (octet).

It involve the elements of group 5th A.

Group 6:

The elements of group 6A gain two electrons to complete the octet and shows -2 charge.

Group 7:

The elements of group 7A gain one electron to complete the octet and shows -1 charge.

Group 8:

The elements of group 8A are noble gases and have complete octet. That's why shows 0 charge.

4 0

3 years ago

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

3 years ago

• Explain, in terms of energy, particles motion & bonds,

Ne4ueva [31]

Explanation:

As the water vapor touches the mirror the particles of the vapor loses energy and they move less then the process Condensation takes place in which the gas turns into water.

3 0

3 years ago

a. How can one tell if a chemical reaction is balanced? (.5 point) b. What information does a complete ionic equation give that

evablogger [386]

Answer:

I think it's C

Explanation:

i think its c b3cause when you guess c always feels right

8 0

2 years ago