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Radda [10]
3 years ago
11

When a gas is rapidly compressed (say, by pushing down a piston) its temperature increases. When a gas expands against a piston,

it cools. Explain these changes in temperature using the kinetic theory, in particular noting what happens to the momentum of molecules when they strike the moving piston.
Physics
1 answer:
shusha [124]3 years ago
4 0

Answer:

Explained in explanation

Explanation:

The first law of thermodynamics states that the change in internal energy of a system(ΔU) is equal to the sum of the net heat transfer into the system(Q) and the net work done on the system(W). In equation, this law is;

ΔU = Q + W

Now, when there's gas inside a container with a movable piston that's tightly fitting, we will assume that the piston can move up and down thereby compressing the gas or allowing the gas to expand against it.

Now these gas molecules inside the container possess kinetic energy. Thus, the internal energy(U) of the system is simply the sum of all the kinetic energies of the individual gas molecules present in the container.

Therefore, if the temperature(T) of the gas increases, then the speed and internal energy(U) of the gas molecules will also increase. In the same way, if the temperature of the gas decreases, the speed and internal energy of the gas molecules would also decrease.

Now, back to the question, when the piston is pushed down, it does work on the gas and the gas does negative work on the piston. Thus, the gas will be get compressed to a smaller space, and thereby making the gas molecules to hit the piston at a faster rate. Thus, there is a decrease in speed and as we saw earlier that when there is a decrease in speed, it means temperature has decreased.

Whereas, when the piston is moved up, the gas does positive work on the piston and the speed of the gas molecules will increase. Like I said earlier that increase in speed means increase in temperature.

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Answer:

x=1.25m

Explanation:

The <em>Center of mass </em>of the system is defined as the point where whole mass of the body is appeared to be  concentrated.

The center of mass of the system is given by

         x=  \frac{m1x1+m2x2}{m1+m2}      

where m1 is mass of man =60 kg

           m2 mass of board =20 kg

let the man be at the origin  x1 =0 , x2 =5m

by substituting in above formula

x =\frac{(60*0)+(20*5)}{60+20} = \frac{100}{80} =1.25 m

x=1.25m

So the center of mass of the system is at 1.25 m from man.

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4 years ago
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A solid sphere is rolling on a surface. what fraction of its total kinetic energy is in the form of rotational kinetic energy ab
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<span>Total KE = KE (rotational) + KE (translational) Moment of inertia of sphere is I = (2/5)mr^2 So KE (rotational) = (1/2) x I x w^2 = (1/2) x (2/5)mr^2 x w^2 = (1/5) x m x r^2 x w^2 KE (translational) = (1/2) x m x v^2 = (1/2) x m x (rw)^2 = (1/2) x m x r^2 x w^2 Hence KE = (1/5) x m x r^2 x w^2 + (1/2) x m x r^2 x w^2 = m x r^2 x w^2 ((1/5) + (1/2)) KE = (7/10) m x r^2 x w^2 Calculating the fraction of rotational kinetic energy to total kinetic energy, = rotational kinetic energy / total kinetic energy = (1/5) x m x r^2 x w^2 / (7/10) m x r^2 x w^2 = (1/5) / (7/10) = 2 / 7 The answer is 2 / 7</span>
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Explanation:

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4 years ago
9. A ball is thrown straight up with an initial speed of 30 m/s. How long will it take to reach the top of its trajectory, and h
ziro4ka [17]

Answer:

1.) Time t = 3.1 seconds

2.) Height h = 46 metres

Explanation:

given that the initial velocity U = 30 m/s

At the top of the trajectory, the final velocity V = 0

Using first equation of motion

V = U - gt

g is negative 9.81m/^2 as the object is going against the gravity.

Substitute all the parameters into the formula

0 = 30 - 9.81t

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Make t the subject of formula

t = 30/9.81

t = 3.058 seconds

t = 3.1 seconds approximately

Therefore, it will take 3.1 seconds to reach to reach the top of its trajectory.

2.) The height it will go can be calculated by using second equation of motion

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Substitutes U, g and t into the formula

h = 30(3.1) - 1/2 × 9.8 × 3.1^2

h = 93 - 47.089

h = 45.911 m

It will go 46 metres approximately high.

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