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Reika [66]
3 years ago
7

Write out the stepwise ka reaction for the diprotic acid h2so3

Chemistry
1 answer:
jasenka [17]3 years ago
8 0
<span>This is a 2 step dissociation reaction. But to find \(\large K_a = \frac{[prodcuts]}{[reactants]}\)</span>
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How many liters of C3H6O are present in a sample weighing 25.6 grams?
Romashka [77]

Answer:

V = 0.0327 L.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:

V=25.6g*\frac{1mL}{0.784g}*\frac{1L}{1000mL}\\\\V=0.0327L

Regards!

7 0
3 years ago
Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas
Shtirlitz [24]
Riley can either change the surface area of the object or can change the slipperiness of the material.
5 0
2 years ago
Read 2 more answers
What is the correct formula for the compound formed between sodium and iodine based on their positions in the periodic table?
Naddika [18.5K]
Sodium (Na) has a +1 charge and Iodine ( I ) has a -1 charge. To create a molecule of sodium iodide the charges will need to balance.

Because the charges on anion and cation are the same; the molecular formula will be NaI
6 0
2 years ago
The molar mass of H2O is 18.01 g/mol. The molar mass of O2 is 32.00 g/mol. What mass of H2O, ins grams, must react to produce 50
Ivan

Answer:

56.28 g

Explanation:

First change the grams of oxygen to moles.

(50.00 g)/(32.00 g/mol) = 1.5625 mol O₂

You have to use stoichiometry for the next part.  Looking at the equation, you can see that for every 2 moles of H₂O, 1 mole of O₂ is produced.  Convert from moles of O₂ to moles of H₂O using this relation.

(1.5625 mol O₂) × (2 mol H₂O/1 mol O₂) = 3.125 mol H₂O

Now convert moles of H₂O to grams.

(3.125 mol) × (18.01 g/mol) = 56.28125 g

Convert to significant figures.

56.28125 ≈ 56.28

5 0
3 years ago
If the forward reaction goes close to completion and has a high yield, what is the expected value of the equilibrium constant (k
Anna007 [38]
If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants. 

<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
</span><span>
Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>

8 0
3 years ago
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