Answer:
1 m/s²
Explanation:
Force = mass × acceleration
F = ma ............ Equation 1
Where F = force, m = mass, a = acceleration.
Given: m = 0.058 kg, a = 10 m/s²
Substitute into equation 1
F = 0.058(10)
F = 0.58 N.
If the same force was used to hit the baseball,
F = m'a
a = F/m'.............. Equation 2
Where M' = mass of the baseball.
Given: F = 0.58 N, m' = 0.58 kg.
Substitute into equation 2
a = 0.58/0.58
a = 1 m/s²
D- All wave lengths refract at the same angle
Explanation- The amount of refraction increases as the wavelength of light decreases. Shorter wavelengths of light are slowed more and consequently experience more bending than the longer wavelengths.
I am pretty sure it is B....
Answer:
-39.2m/s
Explanation:
Using the equation of motion;
v = u + at
Since the ball is thrown upward, the acceleration due to gravity acting on it will be negative, hence a = -g
v = u - gt
Since g = 9.8m/s²
t = 4.0s
u = 0m/s
v = 0 + (-9.8)(4)
v = 0 + (-9.8)(4)
v = -39.2m/s
Hence the speed of the ball before release is -39.2m/s
Answer:
work done lifting the bucket (sand and rope) to the top of the building,
W=67.46 Nm
Explanation:
in this question we have given
mass of bucket=20kg
mass of rope=
height of building= 15 meter
We have to find the work done lifting the bucket (sand and rope) to the building =work done in lifting the rope + work done in lifting the sand
work done in lifting the rope is given as,
=
..............(1)
=
=22.5 Nm
work done in lifting the sand is given as,
.................(2)
Here,
F=mx+c
here,
c=20-18
c=2
m=
m=.133
Therefore,
Put value of F in equation 2
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W=22.5 Nm+44.96 Nm
W=67.46 Nm
