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notka56 [123]
4 years ago
5

Which macromolecules were present in the milk?

Chemistry
1 answer:
lara31 [8.8K]4 years ago
8 0
Proteins,Carbohydrates and Lipids are the macromolecules present in milk.
hope it helps.
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How is Carbon-12 and Carbon-13 different? What’s is the name that describes these two atoms?
Maslowich

Answer:

Carbon 12 and 13 are carbon isotopes, meaning that they have additional neutrons:

Carbon 12 has exactly 6 protons and 6 neutrons ( hence the 12 )

Carbon 13 has 6 protons and 7 neutrons ( hence the 13 )

They differ in the number of neutrons in the nucleus.

Names:

carbon-13, C-13

carbon-12, C-12

4 0
3 years ago
Explain how lines latitude and longitude help people find locations on earth.
Bad White [126]
Latitude and longitude are the x and y axis on a grid. When you're trying to find a location on earth, you need to graph it, so you can pinpoint the location. There is no grid if there is no longitude and/or latitude lines. Without one of the lines, it would be very hard to graph, which will be difficult in finding locations on earth. But hey, I'm not too sure. I recommend looking at other people's answers too and searching it up.
 
8 0
3 years ago
Lithium, sodium and potassium all belong to the same group of the periodic table.
Lady_Fox [76]

Answer:

Yes they are found in same period

4 0
3 years ago
Read 2 more answers
The action force always acts in the ____ direction as the reaction force
andriy [413]

Answer:

opposite

Explanation:

Newtons law explains that for every action force there is an equal and opposite reaction.

6 0
4 years ago
A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?
sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0
4 years ago
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