1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serjik [45]
2 years ago
12

What is the total number of grams of a 32-gram sample of 32P remaining after 71.5 days of decay?

Chemistry
1 answer:
nexus9112 [7]2 years ago
6 0

Answer:

1 g

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 32 g

Time (t) = 71.5 days

Half-life of phosphorus (t½) = 14.3 days

Amount remaining (N) =?

Next, we shall determine the rate of disintegration. This can be obtained as follow:

Half-life of phosphorus (t½) = 14.3 days

Decay constant (K) =?

K = 0.693 / t½

K = 0.693 / 14.3

K = 0.0485 /day

Finally, we shall determine the amount remaining as illustrated below:

Original amount (N₀) = 32 g

Time (t) = 71.5 days

Decay constant (K) = 0.0485 /day

Amount remaining (N) =?

Log (N₀/N) = Kt/2.303

Log (32/N) = 0.0485 × 71.5 / 2.303

Log (32/N) = 3.46775 / 2.303

Log (32/N) = 1.5058

Take the antilog of 1.5058

32/N = antilog (1.5058)

32/N = 32.05

Cross multiply

32 = N × 32.05

Divide both side by 32.05

N = 32 / 32.05

N = 0.998 ≈ 1 g

Thus, the amount remaining after 71.5 days is approximately 1 g.

You might be interested in
How many moles of oxygen are necessary to react completely with four moles of propane (CH)?
steposvetlana [31]

Answer:

20 mole of oxygen

Explanation:

1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20

7 0
3 years ago
Help plsss
PtichkaEL [24]
I think number 47 on the map would be New Mexico i hope i helped out
3 0
3 years ago
Read 2 more answers
How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

6 0
2 years ago
6. List the following particles in size order, from<br> biggest to smallest?
Arte-miy333 [17]

Answer:

the particles, molecules, and gas range from smallest to largest in the following order: electron < proton < atom <...

5 0
3 years ago
2.3 moles of CaBr2 contains how many molecules
kkurt [141]

Avogadro's law states that in every mole of a substance, there are 6.022 \times 10^{23} molecules.

This means that in 2.3 moles, there are 2.3(6.022 \times 10^{23})=\boxed{1.4 \times 10^{24} \text{ (to 2 sf)}}

7 0
2 years ago
Other questions:
  • What is the percentage by mass of solution formed by dissolving 36.0 grams of HCl in 98.0 grams of water?
    7·2 answers
  • S Which could occur in a closed system?
    7·1 answer
  • Which of the following has a central atom that exceeds the octet rule? PCl5 BeF2 H2S CO2
    8·1 answer
  • If you dissolve 3.5 moles of cacl2 in solution how many moles of ca2+ ions and cl- ions will there be in the solution
    12·1 answer
  • For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen,
    15·1 answer
  • If the following elements were to combine with each other, choose which demonstrate the Law of Multiple Proportion. Select all t
    8·1 answer
  • A teacher wants to figure out the amount of a solution that is needed for a titration experiment in a class lab. The class has 1
    12·2 answers
  • What is the name of MnO3
    6·2 answers
  • Need help what is the answer
    10·1 answer
  • How many milliliters are in 8.12 moles of N2
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!