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Lelu [443]
3 years ago
13

A sample of a compound contains 32.0g C and 8.0g H. It’s molar mass is 30.0/mol. What is the compounds molecular formula?

Chemistry
1 answer:
liraira [26]3 years ago
6 0
Answer:
 
<span>Given mass of C is 32.0 grams
</span><span>Given mass of H is 8.0 grams
</span>Molar mass of C is 1212 g/mol 
Molar mass of H is 1.01 g/mol

Thus
<span><span><span><span>32.0 grams of C </span><span>8.0 grams of H </span></span><span><span>→<span>3212</span>=2.66 moles of C</span><span>→<span>81.01</span>=7.92 moles of H</span></span></span><span><span><span>32.0 grams of C </span><span>→<span>3212</span>=2.66 moles of C</span></span><span><span>8.0 grams of H </span><span>→<span>81.01</span>=7.92 moles of H</span></span></span></span>

<span>When we divide 7.92 by 2.66 we obtain 2.977 which is approximately 3. This means that the ratio of atoms of </span><span>CC</span><span> to the atoms of </span><span>HH</span><span> is 1:3.</span>

<span>Thus, empirical formula for the compound is </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span>.

<span>Molar mass of </span><span><span>C<span>H3</span></span><span>C<span>H3</span></span></span><span> is </span><span><span>1⋅12+3⋅1.01=15.03</span><span>1⋅12+3⋅1.01=15.03</span></span><span>. Since molar mass of the compound we have to find is </span><span>3030</span><span> g/mol we have tu multiply subscripts by 2.</span>

<span>Thus, final compound is </span><span><span><span>C2</span><span>H6</span></span><span><span>C2</span><span>H6</span></span></span>.
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When 5.58g H2 react by the following balanced equation, 32.8g H2O are formed. What is the percent yield of the reaction? 2H2(g)+
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Answer:

D) 65.7%

Explanation:

Based on the reaction:

2H2(g)+O2(g)⟶2H2O(l)

<em>2 moles of hydrogen produce 2 moles of water assuming an excess of oxygen.</em>

<em />

To find percent yield of the reaction we need to find theoretical yield (The yield assuming all hydrogen reacts producing water). With theoretical yield and actual yield (32.8g H₂O) we can determine percent yield as 100 times the ratio between actual yield and theoretical yield.

<em>Theoretical yield:</em>

Moles of 5.58g H₂:

5.58g H₂ ₓ (1 mol / 2.016g) = 2.768 moles H₂

As 2 moles of H₂ produce 2 moles of H₂O, if all hydrogen reacts will produce 2.768 moles H₂O. In grams:

2.768 moles H₂O ₓ (18.015g / mol) =

49.86g H₂O is theoretical yield

<em>Percent yield:</em>

Percent yield = Actual yield / Theoretical yield ₓ 100

32.8g H₂O / 49.86g ₓ 100 =

65.7% is percent yield of the reaction

<h3>D) 65.7% </h3>

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