Explanation:
The equation for the average is: (sum of all data values/ (total number of data values)
Answer: (e) The pressure in the container increases but does not double.
Explanation:
To solve this, we need to first remember our gas law, Boyle's law states that the pressure and volume of a gas have an inverse relationship. That is, If volume increases, then pressure decreases and vice versa, when temperature is held constant. Therefore, increasing the volume in this case does not double the pressure owning to out gas law, but an increase in pressure would be noticed if temperature is constant
Answer:
Both
compounds in left hand side of the equation is called reactants.
compounds in right hand side of the equation is called products.
so ans is both water and carbon di oxide
Explanation:
The balanced chemical equation for the formation ammonia is
N2(g) + 3H2(g) ----> 2NH3(g) .
The balanced chemical equations explains that the same number of each element exist as reactants and products. The coefficients in a balanced equation must be the simplest whole number ratio. Mass is always conserved in chemical reactions.
For the formation of ammonia, the chemical equation is
N2(g) + H2(g) ----> NH3(g)
Balancing the chemical reaction, we can write,
N2(g) + 3H2(g) ----> 2NH3(g) .
This equation shows two nitrogen entering the reaction together and two hydrogens entering the reaction together. Since NH3 is multiplied by a coefficient of 2 there are now 2 nitrogen and 6 hydrogens. The 6 hydrogens come from the 2 multiplied by the subscript of 3. This is the balanced chemical reaction.
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I believe the statement above is true. <span>A </span>carbohydrate<span> is a </span>biological molecule<span> consisting of </span>carbon<span> (C), </span>hydrogen<span> (H) and </span>oxygen<span> (O) atoms, usually with a hydrogen–oxygen </span>atom ratio of 2:1. <span>When a </span>carbohydrate<span> is broken into its component sugar molecules by </span>hydrolysis<span> (e.g. sucrose being broken down into glucose and fructose), this is termed saccharification.</span>
